Python 将tempfile.TemporaryFile分配给变量并执行时出错
假设我的类如下所示,所有相关的导入都已完成:Python 将tempfile.TemporaryFile分配给变量并执行时出错,python,Python,假设我的类如下所示,所有相关的导入都已完成: class LargeRequest(server.Request): memory_limit = 1024*1024*25 temp_type = tempfile.TemporaryFile def parse_multipart(self, fp, pdict): while loop_condition: if self.temp_type.__name__ == 'Spoo
class LargeRequest(server.Request):
memory_limit = 1024*1024*25
temp_type = tempfile.TemporaryFile
def parse_multipart(self, fp, pdict):
while loop_condition:
if self.temp_type.__name__ == 'SpooledTemporaryFile':
data = self.temp_type(max_size=self.memory_limit)
else:
data = self.temp_type()
...
data.write('stuff')
当我运行此命令时,我得到一个错误:
File "/home/user/workspace/twisted/server.py", line 226, in parse_multipart
data = self.temp_type()
File "/usr/lib/python2.7/tempfile.py", line 484, in TemporaryFile
if 'b' in mode:
exceptions.TypeError: argument of type 'instance' is not iterable
指的是
此外,如果我只是执行以下操作,则不会发生此错误:
data = tempfile.TemporaryFile()
但我希望有更多的灵活性。我做错了什么?
temp\u type
成为实例方法self.temp\u type()
调用beenTemporaryFile(self)
请尝试以下操作:
temp_type = staticmethod(tempfile.TemporaryFile)