Python密码生成器
我正在尝试用Python创建一个密码生成器,它必须包含大写字母、小写字母和数字,并且长度必须在6到20个字符之间Python密码生成器,python,python-2.7,passwords,Python,Python 2.7,Passwords,我正在尝试用Python创建一个密码生成器,它必须包含大写字母、小写字母和数字,并且长度必须在6到20个字符之间 import random import string def password_gen(): while True: length = random.randint(6,20) pwd = [] for i in range(length): p
import random
import string
def password_gen():
while True:
length = random.randint(6,20)
pwd = []
for i in range(length):
prob = random.random()
if prob < 0.34:
char = random.choice(string.ascii_lowercase)
pwd.append(char)
elif prob < 0.67:
char = random.choice(string.ascii_uppercase)
pwd.append(char)
else:
char = str(random.randint(0,9))
pwd.append(char)
pwd = ''.join(pwd)
#check password here
return pwd
随机导入
导入字符串
def password_gen():
尽管如此:
长度=random.randint(6,20)
pwd=[]
对于范围内的i(长度):
prob=random.random()
如果prob<0.34:
char=random.choice(string.ascii_小写)
pwd.append(字符)
elif概率<0.67:
char=random.choice(string.ascii_大写)
pwd.append(字符)
其他:
char=str(random.randint(0,9))
pwd.append(字符)
pwd=''.join(pwd)
#在这里检查密码
返回pwd
但是,我在检查密码以确保它包含前面列出的所需字符时遇到问题。我不确定是否/如何使用continue语句。如有任何帮助,将不胜感激 我认为,如果您只是预先处理这些问题,那么确保满足基本要求会容易一些
import random
import string
def generate_pw():
length = random.randint(6,20) - 3
pwd = []
pwd.append(random.choice(string.ascii_lowercase))
pwd.append(random.choice(string.ascii_uppercase))
pwd.append(str(random.randint(0,9)))
# fill out the rest of the characters
# using whatever algorithm you want
# for the next "length" characters
random.shuffle(pwd)
return ''.join(pwd)
这将确保您的密码具有所需的字符。例如,对于其余的字符,您可以只使用所有字母数字字符的列表,然后调用random.choice
length
次。您可以使用isupper()和islower()函数来获取密码是否包含大写和小写
import random
import string
def password_gen():
lower_case_letter = random.choice(string.ascii_lowercase)
upper_case_letter = random.choice(string.ascii_uppercase)
number = random.choice(string.digits)
other_characters = [
random.choice(string.ascii_letters + string.digits)
for index in range(random.randint(3, 17))
]
all_together = [lower_case_letter, upper_case_letter] + other_characters
random.shuffle(all_together)
return ''.join(all_together)
e、 g
密码生成器更详细,您可以得到任何您想要的数字,但它输出一个模式,首先添加字母,然后添加数字,最后添加符号
非常感谢。这似乎是一个更简单的回答问题的方法
upper=0
lower=0
for i in range(length):
if (pwd[i].islower()):
upper=1
elif (pwd[i].isupper()):
lower=1
import random
letters = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z', 'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']
numbers = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9']
symbols = ['!', '#', '$', '%', '&', '(', ')', '*', '+']
print("Welcome to the PyPassword Generator!")
nr_letters= int(input("How many letters would you like in your password?\n"))
nr_symbols = int(input(f"How many symbols would you like?\n"))
nr_numbers = int(input(f"How many numbers would you like?\n"))
passwordlength = nr_letters + nr_numbers + nr_symbols
chars = ""
for x in range (0, nr_letters):
char = random.choice(letters)
chars += char
nums = ""
for y in range (0, nr_numbers):
num = random.choice(numbers)
nums+=num
syms = "" # string accumulator
for z in range (0, nr_symbols):
symb = random.choice(symbols)
syms += symb
print(f"Here is your password: {chars}{nums}{syms}")