Python 循环浏览URL列表，运行BeautifulSoup，写入文件

我有一个要运行的URL列表，使用BeautifulSoup清理并保存到.txt文件

import urllib
from bs4 import BeautifulSoup


x = ["https://www.sec.gov/Archives/edgar/data/1000298/0001047469-13-002555.txt",
"https://www.sec.gov/Archives/edgar/data/1001082/0001104659-13-011967.txt"]

for url in x:

    #I want to open the URL listed in my list

    fp = urllib.request.urlopen(url)
    test = fp.read()
    soup = BeautifulSoup(test,"lxml")
    output=soup.get_text()

    #and then save the get_text() results to a unique file.

    file=open("url.txt","w",encoding='utf-8')
    file.write(output)
    file.close()

这是我现在的代码，列表中只有几个项目，txt文件中会有更多的项目，但现在它保持简单

循环工作时，它将两个URL的输出传递到URL.txt文件。我希望列表中的每个实例都输出到其唯一的.txt文件中

import urllib
from bs4 import BeautifulSoup


x = ["https://www.sec.gov/Archives/edgar/data/1000298/0001047469-13-002555.txt",
"https://www.sec.gov/Archives/edgar/data/1001082/0001104659-13-011967.txt"]

for url in x:

    #I want to open the URL listed in my list

    fp = urllib.request.urlopen(url)
    test = fp.read()
    soup = BeautifulSoup(test,"lxml")
    output=soup.get_text()

    #and then save the get_text() results to a unique file.

    file=open("url.txt","w",encoding='utf-8')
    file.write(output)
    file.close()

---

谢谢你看。最好是George为列表中的每个项目创建不同的文件名，如下所示：

import urllib
from bs4 import BeautifulSoup


x = ["https://www.sec.gov/Archives/edgar/data/1000298/0001047469-13-002555.txt",
"https://www.sec.gov/Archives/edgar/data/1001082/0001104659-13-011967.txt"]

for index , url in enumerate(x):

    #I want to open the URL listed in my list

    fp = urllib.request.urlopen(url)
    test = fp.read()
    soup = BeautifulSoup(test,"lxml")
    output=soup.get_text()

    #and then save the get_text() results to a unique file.

    file=open("url%s.txt" % index,"w",encoding='utf-8')
    file.write(output)
    file.close()

---

你能在enumerate（x）中为i，url执行

操作吗？

并使用

i

构建url文件名？我会这样做的！下面的解释很好。