Python 不应使用正则表达式输出打印列表
输出不是预期的。我希望它在“系统”目录下打印与“系统”相关的所有差异,并在“接口”目录下打印与“接口”相关的所有差异。“{…}”也没有打印,即使我有一个语句来捕捉它。代码如下:Python 不应使用正则表达式输出打印列表,python,printing,logic,conditional-statements,Python,Printing,Logic,Conditional Statements,输出不是预期的。我希望它在“系统”目录下打印与“系统”相关的所有差异,并在“接口”目录下打印与“接口”相关的所有差异。“{…}”也没有打印,即使我有一个语句来捕捉它。代码如下: import re template_list = ['system','interfaces'] directory = '/templates/juniper/junos/vfirewall/' diff = """[edit system name-server] 8.8.8.8 { ... } + 4
import re
template_list = ['system','interfaces']
directory = '/templates/juniper/junos/vfirewall/'
diff = """[edit system name-server]
8.8.8.8 { ... }
+ 4.4.4.4;
[edit interfaces ge-0/0/0 unit 0 family inet]
+ address 10.20.30.10/24;
- address 10.50.30.10/24;
[edit interfaces]
+ ge-0/0/1 {
+ unit 2 {
+ family inet {
+ address 10.50.80.10/24;
+ }
+ }
+ }""".splitlines()
for template in template_list:
print("{}{}".format(directory,template))
for line in diff:
if(re.match('\[edit\s({})'.format(template),line)):
print('{}'.format(line))
elif(re.match('\{ ... \}',line)):
print('{}'.format(line))
elif(re.match('^\-',line)):
print('{}'.format(line))
elif(re.match('^\+',line)):
print('{}'.format(line))
elif(re.match('\[edit\s\w.+',line)):
break
输出结果如下:
/templates/juniper/junos/vfirewall/system
[edit system name-server]
+ 4.4.4.4;
/templates/juniper/junos/vfirewall/interfaces
>>>
预期产出:
/templates/juniper/junos/vfirewall/system
[edit system name-server]
8.8.8.8 { ... }
+ 4.4.4.4;
/templates/juniper/junos/vfirewall/interfaces
[edit interfaces ge-0/0/0 unit 0 family inet]
+ address 10.20.30.10/24;
- address 10.50.30.10/24;
[edit interfaces]
+ ge-0/0/1 {
+ unit 2 {
+ family inet {
+ address 10.50.80.10/24;
+ }
+ }
+ }
两个主要问题:
re.search()
而不是re.match()
,因为后者只在字符串的开头匹配(这相当于以^
开始re)
中的
应该进行转义,以与字面上的匹配,-
不需要进行转义
工作版本:
import re
template_list = ['system','interfaces']
directory = '/templates/juniper/junos/vfirewall/'
diff = """[edit system name-server]
8.8.8.8 { ... }
+ 4.4.4.4;
[edit interfaces ge-0/0/0 unit 0 family inet]
+ address 10.20.30.10/24;
- address 10.50.30.10/24;
[edit interfaces]
+ ge-0/0/1 {
+ unit 2 {
+ family inet {
+ address 10.50.80.10/24;
+ }
+ }
+ }""".splitlines()
for template in template_list:
print("{}{}".format(directory,template))
for line in diff:
if(re.search(r'\[edit\s({})'.format(template),line)):
print('{}'.format(line))
elif(re.search(r'\{ \.\.\. \}',line)):
print('{}'.format(line))
elif(re.search(r'^-',line)):
print('{}'.format(line))
elif(re.search(r'^\+',line)):
print('{}'.format(line))
elif(re.search(r'\[edit\s\w.+',line)):
break
创建正则表达式时使用原始字符串。当然可以,但在包含原始字符串时仍然无法解决我的问题。您还需要使用
re.search
而不是re.match
。