Python 求这个矩阵的对角线

我正在尝试创建一个函数，该函数将从列表中的列表中获取对角线，也就是我的单词搜索难题的矩阵

def get_left_up (start_x, start_y, board):
word = []
for row in range (start_x, -1,-1):
    for col in range (start_y,-1, -1):
        word.append(board[row][col])
word = ''.join(word)
return word

get_left_down (start_x, start_y, board):
word = []
for row in range (start_x,len(board)):
    for col in range (start_y,-1,-1):
        word.append(board[row][col])
word = ''.join(word)
return word

def get_right_up (start_x, start_y, board):
word= []
for row in range (start_x,-1,-1):
    for col in range (start_y,len(board)):
        word.append(board[row][col])
word = ''.join(word)
return word

def get_right_down (start_x, start_y, board):
word = []
for row in range (start_x, len(board)):
    for col in range (start_y,len(board)):
      word.append(board[row][col])
word = ''.join(word)
return word

---

到目前为止，那些我应该处理的功能。然而，有点不对劲。我打算把第一个字母的坐标作为参数，从搜索到的单词匹配到棋盘上，并从对角线的每个方向连接字符

对于右下对角线，您需要在同一迭代中增加x-和y-值，而不是循环特定行的所有列条目

def get_right_down (start_x, start_y, board):
   word = []
   col = start_y
   for row in range (start_x, len(board)):
      if col >= len(board):
         break
      word.append(board[row][col])
      col = col + 1
   return ''.join(word)

---

您应该只有一个同时更新列和行号的循环，而不是两个重叠循环。您可以使用

while

循环，测试您是否留在板上。