Python 无法运行SCON获取导入错误
我已经安装了scons 2.3.2和python 2.4 运行scons时,我看到以下错误:Python 无法运行SCON获取导入错误,python,scons,Python,Scons,我已经安装了scons 2.3.2和python 2.4 运行scons时,我看到以下错误: scons Import failed. Unable to find SCons files in: /usr/bin/../engine /usr/bin/scons-local-2.3.2 /usr/bin/scons-local /usr/lib/scons-2.3.2 /usr/lib/scons-2.3.2 /usr/local/lib/scons-2.3.2 /
scons
Import failed. Unable to find SCons files in:
/usr/bin/../engine
/usr/bin/scons-local-2.3.2
/usr/bin/scons-local
/usr/lib/scons-2.3.2
/usr/lib/scons-2.3.2
/usr/local/lib/scons-2.3.2
/usr/lib/python2.4/site-packages/scons-2.3.2
/usr/lib/python2.4/site-packages/scons-2.3.2
/usr/local/lib/python2.4/site-packages/scons-2.3.2
/usr/lib64/scons-2.3.2
/usr/lib/scons
/usr/lib/scons
/usr/local/lib/scons
/usr/lib/python2.4/site-packages/scons
/usr/lib/python2.4/site-packages/scons
/usr/local/lib/python2.4/site-packages/scons
/usr/lib64/scons
Traceback (most recent call last):
File "/usr/bin/scons", line 190, in ?
import SCons.Script
File "/usr/lib/scons/SCons/Script/__init__.py", line 76, in ?
import SCons.Environment
File "/usr/lib/scons/SCons/Environment.py", line 48, in ?
import SCons.Defaults
File "/usr/lib/scons/SCons/Defaults.py", line 52, in ?
import SCons.Tool
File "/usr/lib/scons/SCons/Tool/__init__.py", line 50, in ?
import SCons.Scanner.C
File "/usr/lib/scons/SCons/Scanner/C.py", line 36, in ?
import SCons.cpp
File "/usr/lib/scons/SCons/cpp.py", line 398
p = self.stack[-1] if self.stack else self.default_table
^
SyntaxError: invalid syntax
我做了一个查找,发现SCons存在于/usr/lib/SCons中。我不知道为什么斯科斯不能把它捡起来
我遗漏了什么?问题(从回溯的底部)是语法错误:
p = self.stack[-1] if self.stack else self.default_table
^
SyntaxError: invalid syntax
这是因为您运行的Python版本不支持条件表达式:
在2.5中添加了对该语法的支持,请参见谢谢!scons网站上提到的python 2.4就足够了。这可能是因为在早期的草案中声明,这将在2.4中实现。请注意,SCons 2.3.2(一旦它正常运行)还应该警告您,所有2.7之前版本的Python都已弃用。Python2.7现在是开发的底层版本,因为我们正在向Python2+3源代码库的组合方向发展。