Python Django：传递api'；将json转换为模板以在表中使用_Python_Json_Django_Api

Python Django：传递api'；将json转换为模板以在表中使用

python json django api

Python Django：传递api'；将json转换为模板以在表中使用,python,json,django,api,Python,Json,Django,Api,目前，我在my views.py文件中有搜索函数json_search，如下所示： def json_search(request): query = request.GET.get('query') api_key = locu_api url = 'https://api.locu.com/v1_0/venue/search/?api_key=' + api_key locality = query.replace(' ', '%20') final_

目前，我在my views.py文件中有搜索函数json_search，如下所示：

def json_search(request):
    query = request.GET.get('query')
    api_key = locu_api
    url = 'https://api.locu.com/v1_0/venue/search/?api_key=' + api_key
    locality = query.replace(' ', '%20')
    final_url = url + "&locality=" + locality + "&category=restaurant"
    json_obj = urllib2.urlopen(final_url)
    data = json.load(json_obj)
    json_data = {}
    return HttpResponse(json.dumps(data), content_type='application/json')

def json_search(request):
query = request.GET.get('query')
api_key = locu_api
url = 'https://api.locu.com/v1_0/venue/search/?api_key=' + api_key
locality = query.replace(' ', '%20')
final_url = url + "&locality=" + locality + "&category=restaurant"
json_obj = urllib2.urlopen(final_url)
decoded_data = json.load(json_obj)
return render(request, 'loc_search.html',
                   {'objects': decoded_data['objects']})

我目前正在通过我主页上的一个表单使用如下url调用它：

urlpatterns = patterns(
    "",
    url(r"^$", TemplateView.as_view(template_name="homepage.html"), name="home"),
    url(r"^admin/", include(admin.site.urls)),
    url(r"^account/", include("account.urls")),
    url(r"^loc_search/$", 'project_name.views.json_search', name="search"),
)

{"meta": {"limit": 25, "cache-expiry": 3600}, "objects": [{"name": "Pizza Hut delivery", "locality": "Norwich", "website_url": null, "cuisines": [], "region": "Norfolk", "long": 1.27727303158181, "phone": "01603 488900", "postal_code": null, "categories": ["other", "restaurant"], "has_menu": false, "country": "United Kingdom", "lat": 52.6564553358682, "id": "00388fe53e4c9f5e897d", "street_address": null, "resource_uri": "/v1_0/venue/00388fe53e4c9f5e897d/"}, {"name": "Thai Lanna", "locality": "Norwich", "website_url": "http://www.thailannanorwich.co.uk", "cuisines": [], "region": "Norfolk", "long": 1.2788060400004, "phone": "01603 625087", "postal_code": "NR2 1AQ", "categories": ["other", "restaurant"], "has_menu": true, "country": "United Kingdom", "lat": 52.6273547550005, "id": "0452369b7789e15bb624", "street_address": "24 Bridewell Alley", "resource_uri": "/v1

<ul>
{% for obj in objects %}
    <li>{{ obj.name }} - {{ obj.locality }}</li>
{% endfor %}
</ul>

我想做的是在api的json中用字段name:和phone:填充一个表，我目前已经设置了表：

<body>
<table data-toggle="table" data-url="{% url 'search' %}" data-cache="false" data-height="299">
<thead>
    <tr>
        <th data-field="id">Item ID</th>
        <th data-field="name">Name</th>
        <th data-field="phone">Phone</th>
    </tr>
</thead>

我只是想知道如何准确地传递json数据，以便将搜索范围缩小到所需的字段。我曾尝试使用rendor_to_响应和JsonResponse，但我现在仍在思考如何进行搜索。我觉得我必须改变我的搜索功能，但我不知道怎么做

被卡住了一段时间，所以任何帮助都将不胜感激。

最终设法使其工作，我不得不在我的视图中导入。py

from django.shortcuts import render

然后，我可以修改我的函数，以便通过解析对象数据到我的模板，如下所示：

def json_search(request):
    query = request.GET.get('query')
    api_key = locu_api
    url = 'https://api.locu.com/v1_0/venue/search/?api_key=' + api_key
    locality = query.replace(' ', '%20')
    final_url = url + "&locality=" + locality + "&category=restaurant"
    json_obj = urllib2.urlopen(final_url)
    data = json.load(json_obj)
    json_data = {}
    return HttpResponse(json.dumps(data), content_type='application/json')

def json_search(request):
query = request.GET.get('query')
api_key = locu_api
url = 'https://api.locu.com/v1_0/venue/search/?api_key=' + api_key
locality = query.replace(' ', '%20')
final_url = url + "&locality=" + locality + "&category=restaurant"
json_obj = urllib2.urlopen(final_url)
decoded_data = json.load(json_obj)
return render(request, 'loc_search.html',
                   {'objects': decoded_data['objects']})

然后在我的表格提交后可以这样调用它：

urlpatterns = patterns(
    "",
    url(r"^$", TemplateView.as_view(template_name="homepage.html"), name="home"),
    url(r"^admin/", include(admin.site.urls)),
    url(r"^account/", include("account.urls")),
    url(r"^loc_search/$", 'project_name.views.json_search', name="search"),
)

{"meta": {"limit": 25, "cache-expiry": 3600}, "objects": [{"name": "Pizza Hut delivery", "locality": "Norwich", "website_url": null, "cuisines": [], "region": "Norfolk", "long": 1.27727303158181, "phone": "01603 488900", "postal_code": null, "categories": ["other", "restaurant"], "has_menu": false, "country": "United Kingdom", "lat": 52.6564553358682, "id": "00388fe53e4c9f5e897d", "street_address": null, "resource_uri": "/v1_0/venue/00388fe53e4c9f5e897d/"}, {"name": "Thai Lanna", "locality": "Norwich", "website_url": "http://www.thailannanorwich.co.uk", "cuisines": [], "region": "Norfolk", "long": 1.2788060400004, "phone": "01603 625087", "postal_code": "NR2 1AQ", "categories": ["other", "restaurant"], "has_menu": true, "country": "United Kingdom", "lat": 52.6273547550005, "id": "0452369b7789e15bb624", "street_address": "24 Bridewell Alley", "resource_uri": "/v1

<ul>
{% for obj in objects %}
    <li>{{ obj.name }} - {{ obj.locality }}</li>
{% endfor %}
</ul>


{对象%中obj的百分比}
{{obj.name}}-{{obj.locality}
{%endfor%}

给出期望的结果：）

希望任何有类似问题的人都会觉得这很有帮助

我最终成功地将其导入到我的视图中。py.：

from django.shortcuts import render

然后，我可以修改我的函数，以便通过解析对象数据到我的模板，如下所示：

def json_search(request):
    query = request.GET.get('query')
    api_key = locu_api
    url = 'https://api.locu.com/v1_0/venue/search/?api_key=' + api_key
    locality = query.replace(' ', '%20')
    final_url = url + "&locality=" + locality + "&category=restaurant"
    json_obj = urllib2.urlopen(final_url)
    data = json.load(json_obj)
    json_data = {}
    return HttpResponse(json.dumps(data), content_type='application/json')

def json_search(request):
query = request.GET.get('query')
api_key = locu_api
url = 'https://api.locu.com/v1_0/venue/search/?api_key=' + api_key
locality = query.replace(' ', '%20')
final_url = url + "&locality=" + locality + "&category=restaurant"
json_obj = urllib2.urlopen(final_url)
decoded_data = json.load(json_obj)
return render(request, 'loc_search.html',
                   {'objects': decoded_data['objects']})

然后在我的表格提交后可以这样调用它：

urlpatterns = patterns(
    "",
    url(r"^$", TemplateView.as_view(template_name="homepage.html"), name="home"),
    url(r"^admin/", include(admin.site.urls)),
    url(r"^account/", include("account.urls")),
    url(r"^loc_search/$", 'project_name.views.json_search', name="search"),
)

{"meta": {"limit": 25, "cache-expiry": 3600}, "objects": [{"name": "Pizza Hut delivery", "locality": "Norwich", "website_url": null, "cuisines": [], "region": "Norfolk", "long": 1.27727303158181, "phone": "01603 488900", "postal_code": null, "categories": ["other", "restaurant"], "has_menu": false, "country": "United Kingdom", "lat": 52.6564553358682, "id": "00388fe53e4c9f5e897d", "street_address": null, "resource_uri": "/v1_0/venue/00388fe53e4c9f5e897d/"}, {"name": "Thai Lanna", "locality": "Norwich", "website_url": "http://www.thailannanorwich.co.uk", "cuisines": [], "region": "Norfolk", "long": 1.2788060400004, "phone": "01603 625087", "postal_code": "NR2 1AQ", "categories": ["other", "restaurant"], "has_menu": true, "country": "United Kingdom", "lat": 52.6273547550005, "id": "0452369b7789e15bb624", "street_address": "24 Bridewell Alley", "resource_uri": "/v1

<ul>
{% for obj in objects %}
    <li>{{ obj.name }} - {{ obj.locality }}</li>
{% endfor %}
</ul>


{对象%中obj的百分比}
{{obj.name}}-{{obj.locality}
{%endfor%}

给出期望的结果：）

希望任何有类似问题的人都会觉得这很有帮助

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