Python 如何让zipfile使用UI包装进行实例化

我一直在尝试使用类库appJar，它是Python的一个很好的基本UI。我有可以执行我需要的功能的工作代码，但是，当我将UI包装在它周围时，它不会运行，并且UI对断点的反馈要少得多

相关代码如下：

def zipdir(path, ziph):
# ziph is zipfile handle
for root, dirs, files in os.walk(fromDirectory):
    for file in files:
        with Archive.progressbar.progressbar(max_value=10) as progress:
            for i in range(1):
                filePath = os.path.join(root, file)
                ziph.write(filePath, relpath(filePath, ""))
                time.sleep(0.1)
                progress.update(i)
def beginBackup(btn):
    return app.questionBox("Ready?", "Click OK ")

上面的设置设置了这些函数，下面的应该运行它，但是没有

try:
    if (beginBackup == True):
        print(beginBackup)
        zipf = zipfile.ZipFile('Python.zip', 'w', zipfile.ZIP_DEFLATED)
        zipdir('tmp/', zipf)
        zipf.close()
        os.rename('Python.zip', "bak" + str(fileName) + ".zip")
        shutil.move("bak" + str(fileName) + ".zip", str(toDirectory) + "/bak" + str(fileName) + ".zip")
else:
    raise Exception("Something went wrong")
except Exception as e:
    app.warningBox("Error", "Something went wrong: {}".format(str(e)))

我觉得这是因为我把代码放在了错误的地方，因为我觉得它从来没有实例化备份过程

以下是完整的代码：

import os
import zipfile
import shutil
import time
from os.path import relpath
from appJar import gui

# Global Variables
fromDirectory = ""
toDirectory = ""
fileName = time.time()
fileVersion = 1.2

# Setting up the mechanism
def backupsource(btn):
    fromDirectory = app.directoryBox(title="Source")

def backupdest(btn):
    toDirectory = app.directoryBox(title="Destination")

def zipdir(path, ziph):
    # ziph is zipfile handle
    for root, dirs, files in os.walk(fromDirectory):
        for file in files:
            with Archive.progressbar.progressbar(max_value=10) as progress:
                for i in range(1):
                    filePath = os.path.join(root, file)
                    ziph.write(filePath, relpath(filePath, ""))
                    time.sleep(0.1)
                    progress.update(i)
def beginBackup(btn):
    return app.questionBox("Ready?", "Click OK ")

# Open the GUI
app = gui()
app.showSplash("Simple zip v. 1.2", fill="grey", stripe="#ADDFAD", fg="white", font=44)

# Setup the visual styles of the app
app.setTitle("Simple Zip")
app.setIcon("img/logo.ico")
app.setGeometry(400, 300)
app.setResizable(canResize=True)

# Items inside of the GUI
app.addLabel("title", "Welcome to the simple backup utility")
app.setLabelBg("title", "gray")
app.addLabel("Backup", "Label goes here")

# Setup source buttons
app.addButton("Source", backupsource)
app.addButton("Destination", backupdest)

# Begin Backup section
app.addButton("Backup!", beginBackup)

# start the GUI
app.go()

try:
    if (beginBackup == True):
        print(beginBackup)
        zipf = zipfile.ZipFile('Python.zip', 'w', zipfile.ZIP_DEFLATED)
        zipdir('tmp/', zipf)
        zipf.close()
        os.rename('Python.zip', "bak" + str(fileName) + ".zip")
        shutil.move("bak" + str(fileName) + ".zip", str(toDirectory) + "/bak" + str(fileName) + ".zip")
else:
    raise Exception("Something went wrong")   

 except Exception as e:
        app.warningBox("Error", "Something went wrong: {}".format(str(e)))

def beginBackup(btn):
    if not app.questionBox("Ready?", "Click OK"):
      app.warningBox("Error", "Cancelled")
    else:
      try:
        zipf = zipfile.ZipFile('Python.zip', 'w', zipfile.ZIP_DEFLATED)
        zipdir('tmp/', zipf)
        zipf.close()
        shutil.move('Python.zip', str(toDirectory) + "/bak" + str(fileName) + ".zip")
      except Exception as e:
        app.warningBox("Error", "Something went wrong: {}".format(str(e)))

---

我发现的第一个错误是

os.renames

，它不存在。但我不能建议像这样轻率地发现错误。我会用异常包装器（exceptionwrapper）重写它，并短路无用的

rename

命令，因为

shutil.move

可以处理重命名和跨文件系统移动

然后您执行

app.go（）

但没有任何内容通过这一行。这是GUI主循环。从现在起，

appJar

将分派事件。您不再控制主例程

因此，所有操作都必须在此处完成（按下按钮时激活代码）：

将弹出一个窗口，不再执行任何操作。应将其替换为完整代码：

import os
import zipfile
import shutil
import time
from os.path import relpath
from appJar import gui

# Global Variables
fromDirectory = ""
toDirectory = ""
fileName = time.time()
fileVersion = 1.2

# Setting up the mechanism
def backupsource(btn):
    fromDirectory = app.directoryBox(title="Source")

def backupdest(btn):
    toDirectory = app.directoryBox(title="Destination")

def zipdir(path, ziph):
    # ziph is zipfile handle
    for root, dirs, files in os.walk(fromDirectory):
        for file in files:
            with Archive.progressbar.progressbar(max_value=10) as progress:
                for i in range(1):
                    filePath = os.path.join(root, file)
                    ziph.write(filePath, relpath(filePath, ""))
                    time.sleep(0.1)
                    progress.update(i)
def beginBackup(btn):
    return app.questionBox("Ready?", "Click OK ")

# Open the GUI
app = gui()
app.showSplash("Simple zip v. 1.2", fill="grey", stripe="#ADDFAD", fg="white", font=44)

# Setup the visual styles of the app
app.setTitle("Simple Zip")
app.setIcon("img/logo.ico")
app.setGeometry(400, 300)
app.setResizable(canResize=True)

# Items inside of the GUI
app.addLabel("title", "Welcome to the simple backup utility")
app.setLabelBg("title", "gray")
app.addLabel("Backup", "Label goes here")

# Setup source buttons
app.addButton("Source", backupsource)
app.addButton("Destination", backupdest)

# Begin Backup section
app.addButton("Backup!", beginBackup)

# start the GUI
app.go()

try:
    if (beginBackup == True):
        print(beginBackup)
        zipf = zipfile.ZipFile('Python.zip', 'w', zipfile.ZIP_DEFLATED)
        zipdir('tmp/', zipf)
        zipf.close()
        os.rename('Python.zip', "bak" + str(fileName) + ".zip")
        shutil.move("bak" + str(fileName) + ".zip", str(toDirectory) + "/bak" + str(fileName) + ".zip")
else:
    raise Exception("Something went wrong")   

 except Exception as e:
        app.warningBox("Error", "Something went wrong: {}".format(str(e)))

def beginBackup(btn):
    if not app.questionBox("Ready?", "Click OK"):
      app.warningBox("Error", "Cancelled")
    else:
      try:
        zipf = zipfile.ZipFile('Python.zip', 'w', zipfile.ZIP_DEFLATED)
        zipdir('tmp/', zipf)
        zipf.close()
        shutil.move('Python.zip', str(toDirectory) + "/bak" + str(fileName) + ".zip")
      except Exception as e:
        app.warningBox("Error", "Something went wrong: {}".format(str(e)))

---

所以现在，如果在回调中发生任何事情，您会得到一个很好的警告框，告诉您它到底是什么（无法打开文件、语法错误等等）

os.rename

=>

os.rename

。当你可以用

shutil.move

完成所有操作时，为什么要重命名+移动？我对

os.rename进行了调整，我可能可以用
shutil.move
完成所有操作，这是我作为控制台应用程序编写时的旧版本。我的想法是创建文件，然后使用shutil移动它，这可能是多余的。我没有使用try/except包装进行测试，但我在获取任何要打印到控制台的内容时遇到了问题。我将进行测试并给出反馈。我编辑了您在这里提到的代码（并更新了上面的帖子）实际上，控制台上没有发布任何内容。我对此还是新手，因此调试或输入详细代码以提供给控制台对我来说仍然是新鲜事。之前有几个错误，但概念上有一个很大的错误。你应该阅读GUI系统。同时，我的回答应该会起到作用。太棒了，谢谢你ou！是的，我在这方面还是很新的，所以你的建议帮助很大，现在我可以看到它阻塞的地方，尽管我现在不知道如何修复它。它看起来几乎像是挂着的，或者我没有给它足够的时间来完成。可能需要添加一个状态栏来监控进度？我不确定按照你的指示，除此之外，其他一切都可以正常工作是一行：
shutil.move（'Python.zip'，str（toDirectory）+“/bak”+str（fileName）+“.zip”）
，它移动文件（我不确定到哪里），但不移动到目标
toDirectory