Python 从fasta文件中查找fastq文件的唯一第一行顶部和底部
我有两个文件,一个是Python 从fasta文件中查找fastq文件的唯一第一行顶部和底部,python,unix,awk,grep,fastq,Python,Unix,Awk,Grep,Fastq,我有两个文件,一个是fasta文件,另一个是fastq文件。我想使用fasta,阅读并搜索fastq文件中的每一行,然后打印顶行和底行。这就是我所拥有的 fasta文件 阅读1 aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa aaaaaaaaaa
fasta
文件,另一个是fastq
文件。我想使用fasta
,阅读并搜索fastq
文件中的每一行,然后打印顶行和底行。这就是我所拥有的
fasta文件
阅读1
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa c
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa g
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa ga
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
@DH1DQQN1:269:C1UKCACXX:1:1107:20386:6577 1:N:0:TTAGGC
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa c
+
CCCFFFFFHGHHHJIJHFDDDB173@8815BDDB###############
@DH1DQQN1:269:C1UKCACXX:1:1114:5718:53821:N:0:TTAGGC
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
+
;@?DBD听起来你想要一个只有唯一序列的fastq 这是一种极为低效的方法,但它应该是有效的。它将您的fastq文件存储为一个列表,希望它不会太大。它只会抛出重复的序列,而不是质量分数或任何东西
fastqFile = list(open(fastq))
out = []
output = open('output.fastq', 'at')
for lineNum, line in enumerate(fastqFile):
if lineNum < 4:
out.append(line)
output.write(line)
else:
if line not in out and lineNum % 4 != 3:
output.write(fastqFile[lineNum - 1])
output.write(line)
output.write(fastqFile[lineNum + 1])
output.write(fastqFile[lineNum + 2])
out.append(fastqFile[lineNum - 1])
out.append(line)
out.append(fastqFile[lineNum + 1])
out.append(fastqFile[lineNum + 2])
fastqFile=list(打开(fastq))
out=[]
输出=打开('output.fastq','at')
对于lineNum,枚举中的行(fastqFile):
如果lineNum<4:
out.append(行)
输出。写入(行)
其他:
如果行未输入输出且行数为%4!=三:
output.write(fastqFile[lineNum-1])
输出。写入(行)
output.write(fastqFile[lineNum+1])
output.write(fastqFile[lineNum+2])
out.append(fastqFile[lineNum-1])
out.append(行)
out.append(fastqFile[lineNum+1])
out.append(fastqFile[lineNum+2])
我想我知道你想说什么,所以这是我的代码。根据请求,它将只接受fasta序列的第一次出现。这可能不是最好的方法,但我对python不太熟悉
# open the file into a list
fasta = open('fasta1.fa', 'r').read().splitlines()
fastq = open('fastq1.fq', 'r').read().splitlines()
# get rid of headers
# if headers important, please indicate in example
fastaseq = [s for s in fasta if not any('>' in t for t in s)]
# get rid of whitespace
fastaseq = filter(None, fastaseq)
fastq = filter(None, fastq)
# new list
newfastq = []
# go through each item in your fasta list
# if it matches, get the line above and below
# put in the new list
for fa in fastaseq:
if fa in fastq:
ind = fastq.index(fa)
printblock = fastq[ind-1:ind+2]
elif fa not in fastq:
printblock = []
if printblock:
newfastq.append(printblock)
# print everything to file
with open('fastq2.fq', 'w') as f:
for block in newfastq:
for item in block:
f.writelines(item + '\n')
除非你有充分的理由自己做这件事,否则使用 法斯塔:
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAC
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAG
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAGA
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAGG
fastq(基于您的,但不完全相同,因为您的输出格式不正确):
代码:
编辑:以上按fastq文件而不是fasta文件的顺序打印记录。如果顺序不重要,您应该使用该方法。否则,您可以将记录添加到字典中,其中键是它们在FASTA文件中的索引,并在最后打印它们,对字典进行排序:
from Bio import SeqIO
import sys
with open("fasta") as fh:
fasta = fh.read().splitlines()
seen = set()
records = {}
for record in SeqIO.parse(open('fastq'), 'fastq'):
seq = str(record.seq)
if seq in fasta and seq not in seen:
seen.add(seq)
records[fasta.index(seq)] = record
for record in sorted(records):
sys.stdout.write(records[record].format('fastq'))
(这里我也使用了
sys.stdout.write
而不是print
,以避免额外的换行。)生物学家,你怎么了。。总是发布最糟糕的格式问题!您需要阅读以了解Stackoverflow和提问时的格式设置工作原理。对此感到抱歉!下一次就不行了,在过去的几个月里,你问了14个问题,所有的问题都很糟糕,都必须彻底检查(似乎大部分是我提出的)。如果你希望社区能帮助你,那么你至少可以做的是正确地格式化你的问题。我只想在fastq中打印一次fasta文件的第一行file@pauloAlmeidaThat不是“最终输出文件”中的内容。您应该在问题中有一个所需输出的示例(我不理解您所说的“在fastq文件中打印一次fasta文件的第一行”是什么意思)。在任何情况下,一旦你有了Biopython对象中的记录,你只能打印你想要的。在我提到的最终输出文件中,第一行只出现了一次!这意味着我在fastq文件中重复了相同序列的行,我想打印第一行,底部和顶部各有一行@paulo AlimeidaThat,这是代码的功能;它只打印该行一次(打印的每个序列都被存储起来,这样就不会打印两次)。@abh,我的原始代码没有根据fasta文件对序列进行排序,现在是这样。
@DH1DQQN1:269:C1UKCACXX:1:1107:20386:6577 1:N:0:TTAGGC
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAC
+
CCCFFFFFHGHHHJIJHFDDDB173@8815BDDB###############
@DH1DQQN1:269:C1UKCACXX:1:1114:5718:53821 1:N:0:TTAGGC
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
+
CCCFFFFFHGHHHJIJHFDDDB173@8815BDDB###############
@DH1DQQN1:269:C1UKCACXX:1:1209:10703:35361 1:N:0:TTAGGC
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
+
@@@FFFFFHGHHHGIJHFDDDDDBDD69@6B-707537BDDDB75@@85
@DH1DQQN1:269:C1UKCACXX:1:1210:18926:75163 1:N:0:TTAGGC
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAG
+
@CCFFFFFHHHHHJJJHFDDD@77BDDDDB077007@B###########
from Bio import SeqIO
with open("fasta") as fh:
fasta = fh.read().splitlines()
seen = set()
for record in SeqIO.parse(open('fastq'), 'fastq'):
seq = str(record.seq)
if seq in fasta and seq not in seen:
seen.add(seq)
print record.format('fastq')
from Bio import SeqIO
import sys
with open("fasta") as fh:
fasta = fh.read().splitlines()
seen = set()
records = {}
for record in SeqIO.parse(open('fastq'), 'fastq'):
seq = str(record.seq)
if seq in fasta and seq not in seen:
seen.add(seq)
records[fasta.index(seq)] = record
for record in sorted(records):
sys.stdout.write(records[record].format('fastq'))