Python 使用beautifulsoup提取url

使用此代码：

url = "https://github.com/searcho=desc&p=1&q=stars%3A%3E1&s=stars&type=Repositoris"
with urllib.request.urlopen(url) as response:

html = response.read()
html = html.decode('utf-8')

with open('page_content.html', 'w', encoding='utf-8') as new_file:

    new_file.write(html)

soup = BeautifulSoup(html,'lxml')

g_data= soup.findAll("a", {"class":"v-align-middle"})

print(g_data[0])

输出为：

---

获取属性的值，

json.loads（）

并将其作为常规python命令使用：

import json
# your other code, up to setting the g_data

data_hydro = g_data[0]['data-hydro-click']
data_hydro = json.loads(data_hydro)
print(data_hydro['payload']['result']['url'])

---

它在json字符串中，这就是为什么很难找到它

html = """
<h3>
<a href="/freeCodeCamp/freeCodeCamp" class="v-align-middle"data-hydro-click="{&quot;event_type&quot;:&quot;search_result.click&quot;,&quot;payload&quot;:{&quot;page_number&quot;:1,&quot;query&quot;:&quot;stars:>1&quot;,&quot;result_position&quot;:1,&quot;click_id&quot;:28457823,&quot;result&quot;:{&quot;id&quot;:28457823,&quot;global_relay_id&quot;:&quot;MDEwOlJlcG9zaXRvcnkyODQ1NzgyMw==&quot;,&quot;model_name&quot;:&quot;Repository&quot;,&quot;url&quot;:&quot;https://github.com/freeCodeCamp/freeCodeCamp&quot;},&quot;originating_request_id&quot;:&quot;EB94:4DE3:1D61C50:2AEAFBA:5A8D8E31&quot;}}" data-hydro-hmac="2b170325f8ff481731dd5f65d85e7e94a356f75bdafce1f9c5cc60d112cbc2f8">freeCodeCamp/freeCodeCamp</a>
</h3>
"""
soup = BeautifulSoup(html, 'lxml')
parsed_json = json.loads(soup.a.get('data-hydro-click'))
parsed_json['payload']['result']['url']
# returns 'https://github.com/freeCodeCamp/freeCodeCamp'

html=”“”
"""
soup=BeautifulSoup（html，“lxml”）
parsed_json=json.load（soup.a.get（'data-hydro-click'））
已解析的_json['payload']['result']['url']
#返回'https://github.com/freeCodeCamp/freeCodeCamp'

我会尝试

标记['result']['url']

它在链接中不是父

h3

标记，不是吗？我现在添加了一张图片请不要发布图片和代码截图。另外，展示您尝试了什么，以及您面临的问题。好的，我将添加我的代码和输出，谢谢！感谢您对DOR的回复，对于这行代码-data hydro=g_data[0]['data-hydro-click']，我得到以下错误：无法分配给操作员以下工作代码：DATAHDRO=g_data[0]['data-hydro-click']DATAHDRO=json.loads（DATAHDRO）print（DATAHDRO['payload']['result']['url']）我的错误，在变量名中使用了非法字符；感谢您指出。