Python 如何通过文件处理从给定的数据帧列中获取唯一对？

dataframe中的示例数据：

对 预期的输出是来自Pair列的唯一对，如下所示： 我在尝试上述代码时得到的结果是： 独特的

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数据有什么问题？如果我使用手动数据，那么它会工作为什么不在数据框中

您可以使用设置方法：

data = (((8, 8), (8, 8), (8, 8), (8, 8), (8, 8)),
  ((6, 7), (7, 7), (7, 7), (7, 6), (6, 7)),
  ((2, 12), (12, 3), (3, 4), (4, 12), (12, 12)))

uniques = []

for col in data:
  for unique in list(set(col)):
    uniques.append(unique)

for x in uniques:
  print(x)

或：

data = (((8, 8), (8, 8), (8, 8), (8, 8), (8, 8)),
  ((6, 7), (7, 7), (7, 7), (7, 6), (6, 7)),
  ((2, 12), (12, 3), (3, 4), (4, 12), (12, 12)))

uniques = []

for col in data:
  uniques += [unique for unique in list(set(col))]

for x in uniques:
  print(x)

可以使用set（）方法从元组列表中删除重复项

 >>> items = [(8, 8), (8, 8), (8, 8), (8, 8), (8, 8),
(6, 7), (7, 7), (7, 7), (7, 6), (6, 7),
(2, 12), (12, 3), (3, 4), (4, 12), (12, 12)]
>>> set_items = set(items)
>>> set_items
{(6, 7), (7, 6), (12, 12), (7, 7), (8, 8), (4, 12), (2, 12), (3, 4), (12, 3)}

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你已经发布了两次完全相同的问题。我建议你删除这一条，任何想发表评论的人都应该在这里这样做：不用列表，只需使用集合。set类型强制执行唯一值，最简单的方法是

set（）

。（这种方法唯一的缺点是集合中的类型需要是可散列的）它不起作用我得到了这个错误/ValueError:value的长度与索引的长度不匹配。。。

data = (((8, 8), (8, 8), (8, 8), (8, 8), (8, 8)),
  ((6, 7), (7, 7), (7, 7), (7, 6), (6, 7)),
  ((2, 12), (12, 3), (3, 4), (4, 12), (12, 12)))

uniques = []

for col in data:
  for unique in list(set(col)):
    uniques.append(unique)

for x in uniques:
  print(x)

data = (((8, 8), (8, 8), (8, 8), (8, 8), (8, 8)),
  ((6, 7), (7, 7), (7, 7), (7, 6), (6, 7)),
  ((2, 12), (12, 3), (3, 4), (4, 12), (12, 12)))

uniques = []

for col in data:
  uniques += [unique for unique in list(set(col))]

for x in uniques:
  print(x)

 >>> items = [(8, 8), (8, 8), (8, 8), (8, 8), (8, 8),
(6, 7), (7, 7), (7, 7), (7, 6), (6, 7),
(2, 12), (12, 3), (3, 4), (4, 12), (12, 12)]
>>> set_items = set(items)
>>> set_items
{(6, 7), (7, 6), (12, 12), (7, 7), (8, 8), (4, 12), (2, 12), (3, 4), (12, 3)}