Python 基于列表列表的第一个元素的平均值

输入是击球手的跑步列表。它应该返回击球手平均得分最高的国家

我试图找到最高的平均值，例如，当下面的列表被传递给我的方法时，它应该返回“巴基斯坦”

我试过：

创建两个词典：

total={'Australia': 31, 'India': 96, 'Pakistan': 231}  
division={'Australia': 1, 'India': 2, 'Pakistan': 3} 

想把两个格言的值分开，找出其中最高的一个

还有其他有效的方法吗

感谢您的帮助。

您可以使用以下代码实现此目的：

import pandas as pd
data = [
    ["Pakistan", 23],
    ["Pakistan", 127],
    ["India", 3],
    ["India", 71],
    ["Australia", 31],
    ["India", 22],
    ["Pakistan", 81]
]
df = pd.DataFrame(data, columns=['country', 'count'])
grouped = df.groupby(['country']).mean().reset_index()
highest = list(grouped.max())
print(highest)

打印：

['Pakistan', '77']

为了实现这一点，您可以使用以下代码：

import pandas as pd
data = [
    ["Pakistan", 23],
    ["Pakistan", 127],
    ["India", 3],
    ["India", 71],
    ["Australia", 31],
    ["India", 22],
    ["Pakistan", 81]
]
df = pd.DataFrame(data, columns=['country', 'count'])
grouped = df.groupby(['country']).mean().reset_index()
highest = list(grouped.max())
print(highest)

打印：

['Pakistan', '77']

---

也许可以用更少的代码行来完成，但这是可行的

def average(data):
    highest = {}
    index = 0
    while True:
        for i in data:
            if i[0] in highest:
                highest[i[0]].append(i[1])
            else:
                highest[i[0]] = [i[1]]
        for i in highest:
            highest[i] = sum(highest[i]) / len(highest[i])
        answer = 0
        for i in highest:
            if highest[i] >= answer:
                answer = i
        return answer
print average(data)

---

也许可以用更少的代码行来完成，但这是可行的

def average(data):
    highest = {}
    index = 0
    while True:
        for i in data:
            if i[0] in highest:
                highest[i[0]].append(i[1])
            else:
                highest[i[0]] = [i[1]]
        for i in highest:
            highest[i] = sum(highest[i]) / len(highest[i])
        answer = 0
        for i in highest:
            if highest[i] >= answer:
                answer = i
        return answer
print average(data)

---

您可以创建一个以国家名称为关键字、以国家计数和分数列表为值的词典。然后，您可以进一步修改用于计算平均值的同一词典，并使用max打印具有最大平均值的国家/地区

代码如下：

>>> a = [
["Pakistan", 23],
["Pakistan", 127],
["India", 3],
["India", 71],
["Australia", 31],
["India", 22],
["Pakistan", 81]
]
>>> 
>>> 
>>> a
[['Pakistan', 23], ['Pakistan', 127], ['India', 3], ['India', 71],         ['Australia', 31], ['India', 22], ['Pakistan', 81]]
>>> d = {}
>>> for l in a:
        if l[0] not in d.keys():
            d.update({l[0]:[1,l[1]]})
        else:
            d[l[0]] = [d[l[0]][0]+1,d[l[0]][1]+l[1]]


>>> #updated list
>>> d
{'Pakistan': [3, 231], 'Australia': [1, 31], 'India': [3, 96]} 
>>> for key,val in d.items():
d[key] = val[1]/val[0]

#Updated dict with average per country
>>> d
{'Pakistan': 77.0, 'Australia': 31.0, 'India': 32.0}

>>> max(d.items())
('Pakistan', 77.0)
>>> 

---

可能有更简单、更通俗的方法，但这就是逻辑所在。

您可以创建一个以国家名称为键、以国家计数和分数为值的词典。然后，您可以进一步修改用于计算平均值的同一词典，并使用max打印具有最大平均值的国家/地区

代码如下：

>>> a = [
["Pakistan", 23],
["Pakistan", 127],
["India", 3],
["India", 71],
["Australia", 31],
["India", 22],
["Pakistan", 81]
]
>>> 
>>> 
>>> a
[['Pakistan', 23], ['Pakistan', 127], ['India', 3], ['India', 71],         ['Australia', 31], ['India', 22], ['Pakistan', 81]]
>>> d = {}
>>> for l in a:
        if l[0] not in d.keys():
            d.update({l[0]:[1,l[1]]})
        else:
            d[l[0]] = [d[l[0]][0]+1,d[l[0]][1]+l[1]]


>>> #updated list
>>> d
{'Pakistan': [3, 231], 'Australia': [1, 31], 'India': [3, 96]} 
>>> for key,val in d.items():
d[key] = val[1]/val[0]

#Updated dict with average per country
>>> d
{'Pakistan': 77.0, 'Australia': 31.0, 'India': 32.0}

>>> max(d.items())
('Pakistan', 77.0)
>>> 

---

可能有更简单、更具python风格的方法，但这就是逻辑所在。

Thia是另一种方法：

lst = [
["Pakistan", 23],
["Pakistan", 127],
["India", 3],
["India", 71],
["Australia", 31],
["India", 22],
["Pakistan", 81]
]
tuples = [tuple(i) for i in lst]
newdata = {}
for k,v in tuples:
    newdata.setdefault(k, []).append(v)
result = {k:(sum(v)/len(v)) for k,v in newdata.items()}
a = max(result)
b = max(result.values())
print "The highest average is %s: %s " % (a,b)

输出：

---

平均值最高的是巴基斯坦：77

这是另一种方式：

lst = [
["Pakistan", 23],
["Pakistan", 127],
["India", 3],
["India", 71],
["Australia", 31],
["India", 22],
["Pakistan", 81]
]
tuples = [tuple(i) for i in lst]
newdata = {}
for k,v in tuples:
    newdata.setdefault(k, []).append(v)
result = {k:(sum(v)/len(v)) for k,v in newdata.items()}
a = max(result)
b = max(result.values())
print "The highest average is %s: %s " % (a,b)

输出：

巴基斯坦的平均值最高：77