如何使Python函数返回静态变量?
我正在尝试构建一个用于检查重复图像哈希的方法。为此,我在表单验证程序中使用了一个嵌套函数。问题是,当我在外部函数中设置一个变量(内部函数的结果)时,对外部变量的任何后续引用都会再次调用内部函数 例如:如何使Python函数返回静态变量?,python,python-3.x,flask,wtforms,Python,Python 3.x,Flask,Wtforms,我正在尝试构建一个用于检查重复图像哈希的方法。为此,我在表单验证程序中使用了一个嵌套函数。问题是,当我在外部函数中设置一个变量(内部函数的结果)时,对外部变量的任何后续引用都会再次调用内部函数 例如: def dupe_check(self, field): def get_hash(): f = field.data img = Image.open(f) imghash = imagehash.dhash(img) f.
def dupe_check(self, field):
def get_hash():
f = field.data
img = Image.open(f)
imghash = imagehash.dhash(img)
f.seek(0)
return imghash
imghash = get_hash()
hashcheck = Sights.query.filter(Sights.image_hash == imghash).first()
if hashcheck == imghash:
print('dupe')
raise ValidationError('duplicate hash!')
else:
print('no dupe')
如果运行时数据库中没有散列,我会打印无重复
,然后上传图像
但是,如果哈希存在于数据库中,当执行到达时,如果hashcheck==imghash:
我会崩溃,因为imghash
似乎再次调用get\u hash()
,而不是简单地返回先前使用imghash=get\u hash()
设置的哈希字符串
您可以在下面看到,imagehash
程序被调用(并崩溃),而不仅仅是哈希字符串
127.0.0.1 - - [17/Sep/2017 17:49:36] "POST /add HTTP/1.1" 500 -
Traceback (most recent call last):
File "/home/mrrg/dev/flaskimg/venv/lib/python3.5/site-packages/flask/app.py", line 1997, in __call__
return self.wsgi_app(environ, start_response)
File "/home/mrrg/dev/flaskimg/venv/lib/python3.5/site-packages/flask/app.py", line 1985, in wsgi_app
response = self.handle_exception(e)
File "/home/mrrg/dev/flaskimg/venv/lib/python3.5/site-packages/flask/app.py", line 1540, in handle_exception
reraise(exc_type, exc_value, tb)
File "/home/mrrg/dev/flaskimg/venv/lib/python3.5/site-packages/flask/_compat.py", line 33, in reraise
raise value
File "/home/mrrg/dev/flaskimg/venv/lib/python3.5/site-packages/flask/app.py", line 1982, in wsgi_app
response = self.full_dispatch_request()
File "/home/mrrg/dev/flaskimg/venv/lib/python3.5/site-packages/flask/app.py", line 1614, in full_dispatch_request
rv = self.handle_user_exception(e)
File "/home/mrrg/dev/flaskimg/venv/lib/python3.5/site-packages/flask/app.py", line 1517, in handle_user_exception
reraise(exc_type, exc_value, tb)
File "/home/mrrg/dev/flaskimg/venv/lib/python3.5/site-packages/flask/_compat.py", line 33, in reraise
raise value
File "/home/mrrg/dev/flaskimg/venv/lib/python3.5/site-packages/flask/app.py", line 1612, in full_dispatch_request
rv = self.dispatch_request()
File "/home/mrrg/dev/flaskimg/venv/lib/python3.5/site-packages/flask/app.py", line 1598, in dispatch_request
return self.view_functions[rule.endpoint](**req.view_args)
File "/home/mrrg/dev/flaskimg/project/sights/views.py", line 74, in add_image
if form.validate_on_submit():
File "/home/mrrg/dev/flaskimg/venv/lib/python3.5/site-packages/flask_wtf/form.py", line 101, in validate_on_submit
return self.is_submitted() and self.validate()
File "/home/mrrg/dev/flaskimg/venv/lib/python3.5/site-packages/wtforms/form.py", line 310, in validate
return super(Form, self).validate(extra)
File "/home/mrrg/dev/flaskimg/venv/lib/python3.5/site-packages/wtforms/form.py", line 152, in validate
if not field.validate(self, extra):
File "/home/mrrg/dev/flaskimg/venv/lib/python3.5/site-packages/wtforms/fields/core.py", line 204, in validate
stop_validation = self._run_validation_chain(form, chain)
File "/home/mrrg/dev/flaskimg/venv/lib/python3.5/site-packages/wtforms/fields/core.py", line 224, in _run_validation_chain
validator(form, self)
File "/home/mrrg/dev/flaskimg/project/sights/forms.py", line 71, in dupe_check
if hashcheck == imghash:
File "/home/mrrg/dev/flaskimg/venv/lib/python3.5/site-packages/imagehash/__init__.py", line 85, in __eq__
return numpy.array_equal(self.hash.flatten(), other.hash.flatten())
AttributeError: 'Sights' object has no attribute 'hash'
我想imghash=get_hash()
会设置从内部函数返回的变量的新实例吗?如何设置一个静态变量来进行操作,并避免对内部函数的额外调用
我还尝试在内部函数的
imghash
上设置全局/非局部,结果相同。据我所知,您的代码尝试将一个Sight对象与ImageHash对象进行比较,但Sight类代码实现仅在两个Sight对象之间进行比较,因此出现错误,我不确定是否理解您的意思。我不是在一个视界内比较。我定义了两个变量:imghash
是从内部函数创建的,hashcheck
是从SQLAlchemy查询创建的。您能告诉我变量hashcheck和imghash的类型吗?啊,我知道了,我有两种不同的变量类型:
和
。规范化变量以进行比较的最佳方法是什么?对于散列值,我认为将对象类型强制转换为字符串以进行比较是合适的,这最终会起作用。谢谢您的帮助@Tung-vs。