python函数中递归深度的控制
我有以下代码:python函数中递归深度的控制,python,python-3.x,recursion,turtle-graphics,fractals,Python,Python 3.x,Recursion,Turtle Graphics,Fractals,我有以下代码: from turtle import * speed(0) def polygon(xangle, steps): n = 360 // xangle # number of sides required for chosen exterior angle for i in range(n): forward(steps) right(xangle) def corner_polygons(xangle, steps):
from turtle import *
speed(0)
def polygon(xangle, steps):
n = 360 // xangle # number of sides required for chosen exterior angle
for i in range(n):
forward(steps)
right(xangle)
def corner_polygons(xangle, steps):
n = 360 // xangle
for i in range(n):
draw_polygon(xangle, steps//5) # draw smaller polygon
forward(steps)
right(xangle)
def double_corner_polygons(xangle, steps):
n = 360 // xangle
for i in range(n):
corner_polygons(xangle, steps//5)
forward(steps)
right(xangle)
第一个函数使用指定的外角(xangle
)和等于步数的边长绘制多边形。第二个函数绘制与以前相同的多边形,但现在在每个角中放置一个较小的多边形。第三个功能更深一层,例如:
double\u corner\u polygons(60150)
给出:
我想添加另一个参数,recursions
,它控制绘图的深度,这样我就不必每次都编写新函数。我似乎不太明白。我迄今为止的努力:
def corner_polygons_recursive(xangle, steps, recs):
n = 360 // xangle
for i in range(n):
for j in range(1, recs+1):
corner_polygons(xangle, steps//5*j)
forward(steps)
right(xangle)
它可能比你想做的要简单,可能类似于:
import turtle
def corner_polygons_recursive(angle, side, depth):
if depth < 1:
return
n = 360 // angle
for _ in range(n):
corner_polygons_recursive(angle, side / 3, depth - 1)
turtle.forward(side)
turtle.right(angle)
corner_polygons_recursive(60, 150, 4)
turtle.exitonclick()
导入海龟
def corner_polygons_recursive(角度、侧面、深度):
如果深度小于1:
返回
n=360//角度
对于范围内的u(n):
角点\多边形\递归(角度、边/3、深度-1)
乌龟。向前(侧)
乌龟。右(角)
角点多边形递归(60,150,4)
turtle.exitonclick()
输出