如何使用python获取此文件中的变量名
这是a.txt文件:如何使用python获取此文件中的变量名,python,dictionary,Python,Dictionary,这是a.txt文件: attackUp = [10, 15] defenceUp = [10, 15] magicUp = [10, 15] attType = [1, 1] weightDown = [10, 15] #装饰器数据 accAttackSword = [100, 100] accAttackSaber = [100, 100] accAttackAx = [100, 100] accAttackHa
attackUp = [10, 15]
defenceUp = [10, 15]
magicUp = [10, 15]
attType = [1, 1]
weightDown = [10, 15]
#装饰器数据
accAttackSword = [100, 100]
accAttackSaber = [100, 100]
accAttackAx = [100, 100]
accAttackHammer = [100, 100]
accAttackSpear = [100, 100]
accAttackFight = [100, 100]
accAttackBow = [100, 100]
accAttackMagicGun = [100, 100]
accAttackMagic = [100, 100]
mStrInstrument = [100, 100]
mStrCharms = [100, 100]
accDefencePhy = [100, 100]
accDefenceMag = [100, 100]
accWeight = [100, 90, 0,0, 100, 90]
#战术书数据
bookTurn = [1, 1]
bookAttackPhy = [100, 100]
bookAttackMag = [100, 100]
bookStrInstrument = [100, 100]
bookStrCharms = [100, 100]
bookDefencePhy = [100, 100]
bookDefenceMag = [100, 100]
bookWeight = [100, 100]
#数据
data = self.owner.get_user_info()
npc = self.create_npc()
name = [self.owner.name,'npc_1']
plvl = [data.get('level'),npc.get('level')]
str = [data.get('power'),npc.get('power')]
ski = [data.get('skill'),npc.get('skill')]
mag = [data.get('magic'),npc.get('magic')]
spd = base.get('speed')[:2]
locX = base.get('locX')
locX = [locX[1],locX[4]]
locY = base.get('locY')
locY = [locY[1],locY[4]]
wName = []; wAttack = []; wDefence = []; wWeight = [];wType = []; target = []
我想得到一个这样的口述:
{'attackUp':attackUp,'defenceUp':defenceUp,'magicUp':magicUp ...}
这是我的代码:
a=open('a.txt', 'rb')
a=a.read()
我能做什么
谢谢
更新:
我使用以下代码:
with open('a.txt', 'rb') as f:
contents = f.read().decode('utf-8-sig')
items = { }
for line in contents.split('\n'):
item = line.split('=')[0].strip()
items[item] = item
b=open('b.txt','wb')
b.write(unicode(items))
但它表明:
{u'': u'', u'accDefencePhy': u'accDefencePhy', u'mStrCharms': u'mStrCharms', ..}
我想去
{ 'accDefencePhy': accDefencePhy, 'mStrCharms': mStrCharms, ..}
那么,如何删除
”
和u
为什么不将该txt文件转换为.py文件,并将其导入到要在其中使用值的模块中呢
而不是
attackup=chardict['attackup']
进口字符
attackup=charattrs.attackup如果从文件中删除
self.
“变量”(Python不知道如何理解它们),则可以获得一个包含所需内容的字典:
import a # This supposes that your file is named a.py instead of a.txt
var_dict = vars(a)
print var_dict['accDefencePhy'] # Yields [100, 100]
(您还可以在var_dict(即
\uu doc\uu
等)中获得一些附加条目,在使用var_dict=vars(a.copy()
复制原始词典后,如果需要,您可以删除这些条目)您希望dict中的“plvl”是什么。?您的文件似乎包含Python代码……所以您希望字典不包含值,而是包含变量名(但不作为字符串)?这是不可能的。字典只能包含对象。。。除非您的代码的作用域中碰巧有accdeffencephy
等,并且您希望将它们的值注入到字典中