Python 如何插入“|&引用；在-&引用；像这样每隔5分钟？

我想做像这张照片，但我不知道插入“|”

这是我的密码

"""test"""
def counts():
    """process"""
    text = input()
    text_abc = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
    for i in text_abc:
        count_text = text.count(i)
        if count_text > 0:
            ans = "-"* count_text
            print("%s : %s"%(i, ans))
counts()

它是这样输出的

my input:"aaaaaaaabbbbbcccdd"
my output:
a : --------
b : -----
c : ---
d : --

我该怎么办？提前感谢您提供的任何帮助。

---

ps.对不起，我的英语不好

最简单的方法就是通过

str.replace（）

将其放入

ans

，默认情况下，它将替换从前面开始的任意数量的事件：

ans = ("-" * count_text).replace('-----', '-----|')

---

您也可以这样做：

ans = "-" * count_text
ans = '|'.join(ans[i:i+5] for i in range(0, len(ans), 5))

完整代码：

def counts():
    """process"""
    text = input()
    text_abc = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
    for i in text_abc:
        count_text = text.count(i)
        if count_text > 0:
            ans = "-" * count_text
            ans = '|'.join(ans[i:i+5] for i in range(0, len(ans), 5))
            print("%s : %s"%(i, ans))

counts()

输出：

例1

例2

---

我使用了collections软件包中的计数器模块，格式也在3.6中，我不确定collections是否适用于低于3.6的版本，请交叉检查

from collections import Counter

"""test"""
def counts():
    """process"""
    text = Counter(input()) # counter returns a list with key as the element and value as it's frequency

    for i in text.keys(): # iterating in keys
        count_text = text[i]  # getting the frequency of that alphabet
        pattern = ['|-' if (_ % 5 == 0 and _ != 0) else '-' for _ in range(count_text)] # creating a list in which we put '|-' if the position if mod of 5 else we just put '-'.
        patternString = ''.join(pattern) # then we convert it to string
        print(f'{i}: {patternString} ')

counts()

---

这是最好的XD

"aaaaaaaabbbbbcccdd"
a : -----|---
b : -----
c : ---
d : --

"aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaabbbbcccccccccccccccccccccddyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy"
a : -----|-----|-----|-----|-----|-----|-----|-
b : ----
c : -----|-----|-----|-----|-
d : --
y : -----|-----|-----|-----|-----|-----|----

from collections import Counter

"""test"""
def counts():
    """process"""
    text = Counter(input()) # counter returns a list with key as the element and value as it's frequency

    for i in text.keys(): # iterating in keys
        count_text = text[i]  # getting the frequency of that alphabet
        pattern = ['|-' if (_ % 5 == 0 and _ != 0) else '-' for _ in range(count_text)] # creating a list in which we put '|-' if the position if mod of 5 else we just put '-'.
        patternString = ''.join(pattern) # then we convert it to string
        print(f'{i}: {patternString} ')

counts()