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Python 将变长列表作为参数传递给线程化函数_Python_List_Parameter Passing_Python Multithreading - Fatal编程技术网

Python 将变长列表作为参数传递给线程化函数

Python 将变长列表作为参数传递给线程化函数,python,list,parameter-passing,python-multithreading,Python,List,Parameter Passing,Python Multithreading,我试图将列表作为参数传递给线程函数。这个列表的长度可能会有所不同,但我不知道怎么做。下面是我正在使用的代码。现在,我只希望能够将列表放入线程函数并在屏幕上打印出来 #!/usr/bin/python import threading import Queue as queue def generateRange(starting_chars=(*args)): print str(starting_chars) for i in range(32,126): q = qu

我试图将列表作为参数传递给线程函数。这个列表的长度可能会有所不同,但我不知道怎么做。下面是我正在使用的代码。现在,我只希望能够将列表放入线程函数并在屏幕上打印出来

#!/usr/bin/python
import threading
import Queue as queue


def generateRange(starting_chars=(*args)):
    print str(starting_chars)


for i in range(32,126):
    q = queue.Queue()
    theArgs = [i,32,32]
    threads = [ threading.Thread(target=generateRange,args=theArgs) ]
    # generateRange([i,32,32]) 
    for th in threads:
        th.daemon = True
        th.start()
我得到了这个错误:

    File "./test.py", line 6
    def generateRange(starting_chars=(*args)):
                                      ^
SyntaxError: invalid syntax

我做错了什么?

您可以将语法更改为此,否则将不定义
args

def generateRange(*starting_chars):
    print str(starting_chars)

我不知道您为什么特别希望将参数命名为“starting_chars”,但是:

def generateRange(*starting_chars):
    print str(starting_chars)

应该可以

def generateRange(*args):
    print str(args)