Python 如何转换类型为“的时间戳列”;“对象”;“适当地”;时间“;类型?
我有一个数据框,其中有一列时间戳,如下所示:Python 如何转换类型为“的时间戳列”;“对象”;“适当地”;时间“;类型?,python,pandas,dataframe,Python,Pandas,Dataframe,我有一个数据框,其中有一列时间戳,如下所示: 0 2016-10-26T00:26:35+00:00 1 2016-10-26T00:26:44+00:00 2 2016-10-26T00:26:37+00:00 3 2016-10-26T00:26:27+00:00 4 2016-10-26T00:26:32+00:00 5 2016-10-26T00:26:37+00:00 6 2
0 2016-10-26T00:26:35+00:00
1 2016-10-26T00:26:44+00:00
2 2016-10-26T00:26:37+00:00
3 2016-10-26T00:26:27+00:00
4 2016-10-26T00:26:32+00:00
5 2016-10-26T00:26:37+00:00
6 2016-10-26T00:26:42+00:00
7 2016-10-26T00:26:42+00:00
8 2016-10-26T00:26:45+00:00
9 2016-10-26T00:26:46+00:00
10 2016-10-26T00:26:42+00:00
11 2016-10-26T00:26:46+00:00
12 2016-10-26T00:26:52+00:00
13 2016-10-26T00:26:56+00:00
14 2016-10-26T00:27:00+00:00
15 2016-10-26T00:27:03+00:00
16 2016-10-26T00:27:06+00:00
17 2016-10-26T00:18:28+00:00
18 2016-10-26T00:18:28+00:00
19 2016-10-26T00:18:35+00:00
20 2016-10-26T00:18:31+00:00
21 2016-10-26T00:18:27+00:00
22 2016-10-26T00:18:34+00:00
23 2016-10-26T00:18:43+00:00
24 2016-10-26T00:18:43+00:00
25 2016-10-26T00:18:43+00:00
26 2016-10-26T00:18:50+00:00
27 2016-10-26T00:19:02+00:00
28 2016-10-26T00:19:05+00:00
29 2016-10-26T00:18:39+00:00
我想将该列转换为适当的“time”类型,以便以后可以使用该时间。我尝试使用pd.to_datetime(df['time'],unit='s',utc=True)
,但收到错误消息:
ValueError: non convertible value 2016-10-26T00:26:35+00:00with the unit 's'
所以问题是什么是正确的转换方式?谢谢 您尝试的操作失败,因为此处的unit param期望输入序列为数字,而在本例中不是,事实上您根本不需要传递任何参数:
In [23]:
pd.to_datetime(df['time'])
Out[23]:
0 2016-10-26 00:26:35
1 2016-10-26 00:26:44
2 2016-10-26 00:26:37
3 2016-10-26 00:26:27
4 2016-10-26 00:26:32
5 2016-10-26 00:26:37
6 2016-10-26 00:26:42
7 2016-10-26 00:26:42
8 2016-10-26 00:26:45
9 2016-10-26 00:26:46
10 2016-10-26 00:26:42
11 2016-10-26 00:26:46
12 2016-10-26 00:26:52
13 2016-10-26 00:26:56
14 2016-10-26 00:27:00
15 2016-10-26 00:27:03
16 2016-10-26 00:27:06
17 2016-10-26 00:18:28
18 2016-10-26 00:18:28
19 2016-10-26 00:18:35
20 2016-10-26 00:18:31
21 2016-10-26 00:18:27
22 2016-10-26 00:18:34
23 2016-10-26 00:18:43
24 2016-10-26 00:18:43
25 2016-10-26 00:18:43
26 2016-10-26 00:18:50
27 2016-10-26 00:19:02
28 2016-10-26 00:19:05
29 2016-10-26 00:18:39
Name: time, dtype: datetime64[ns]
所以这里处理字符串fine
pd.to_datetime(df['time'])
应该在这里工作是的,它可以!谢谢@EdChum!如果你想把你的答案写在回信里,我会投票确认决议。