Python Azure服务总线未从队列检索消息

我正在尝试使用python azure service bus client不断检查队列中是否有包含进程Id的新消息。出于某种原因，每次我初始化azure service bus client时，它都会运行几秒钟，然后输出以下消息：进程已完成，退出代码为-1073741819（0xC0000005）

。我仔细检查了我的队列名称和所有内容，但我不明白问题出在哪里

with servicebus_client:
    receiver = servicebus_client.get_queue_receiver( queue_name=CALC_REQUEST_QUEUE)
    print( "state 1" )
    with receiver:
        print("state")
        for msg in receiver:
            calc_request = json.loads( str( msg ) )
            processing_identifier = calc_request.get( 'processingIdentifier', None )
            print( "Received: " + str( processing_identifier ) )
            calc_config = fetch_calc_configuration( processing_identifier )
            calc_response = invoke_capsule_summary_processing(calc_config)

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如果您只是想连续从某个队列中提取新消息，请尝试以下操作：

import asyncio
from asyncio.tasks import sleep
from azure.servicebus.aio import ServiceBusClient

CONNECTION_STR = ''
QUEUE_NAME = ''


async def main():
    servicebus_client = ServiceBusClient.from_connection_string(conn_str=CONNECTION_STR)

    async with servicebus_client:
        receiver = servicebus_client.get_queue_receiver(queue_name=QUEUE_NAME)
        async with receiver:
            received_msgs = await receiver.receive_messages(max_message_count=10, max_wait_time=5)
            for msg in received_msgs:
                print(str(msg))
                await receiver.complete_message(msg)

loop = asyncio.get_event_loop()
while True : 
    #each 10 seconds to pull messages from queue.
    sleep(10)  
    print('pull messages...')
    loop.run_until_complete(main())

结果:

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我想知道，如果您只是接收并打印信息，会怎么样？这样我们就可以确定这是与接收部件有关的问题，还是与后续处理部件有关的问题。@AdamLing我同意你的建议。我试着只接收并打印信息，但没有成功。在获得打印消息的机会之前，代码会出错。我认为这是接收消息的问题。我想知道是否是消息的内容触发了错误——您发送的消息的内容是什么，它们是通过同一个SDK发送的？请随时在中打开问题以添加更多详细信息。