Python 函数通过字典中的值传递
我正在尝试编写一个程序,检查字典中的操作,并调用与“key”匹配的函数 该程序将根据“键”是什么来解析该行 我的问题是,如何将字符串传递到字典调用的函数中,以便函数能够解析它,因为字符串不总是相同的,字符串的解析方式也不相同Python 函数通过字典中的值传递,python,function,dictionary,pairing,Python,Function,Dictionary,Pairing,我正在尝试编写一个程序,检查字典中的操作,并调用与“key”匹配的函数 该程序将根据“键”是什么来解析该行 我的问题是,如何将字符串传递到字典调用的函数中,以便函数能够解析它,因为字符串不总是相同的,字符串的解析方式也不相同 def format1(opline): # r-type: rd, rs, rt opline = opline.split('', 1)[1] # re
def format1(opline): # r-type: rd, rs, rt
opline = opline.split('', 1)[1] # removes instruction
rd, rs, rt = opline.split() # splits into 3 registers
return rd, rs, rt # returns all registers
inst_match = {'add' : format1} # dictionary (more.
# key/funct pairs
# will be added
instruction_storage = 'add 9 0 255'
instructions = instruction_storage.split()[0] # get key from string
inst_match[instructions](instruction_storage) # passes key to search and string to pass into function
^上面的代码只是一个测试。我最终会从一个包含多行的文件中读取“指令存储”。我不太清楚您到底想要什么,但这里有一个猜测:
def format1(opline, string):
print('format1({!r}, {!r})'.format(opline, string))
opline = opline.split(' ', 1)[1]
rd, rs, rt = opline.split()
return rd, rs, rt
def format2(opline, string):
print('format2({!r}, {!r})'.format(opline, string))
opline = opline.split(' ', 1)[1]
rd, rs, rt = opline.split()
return rd, rs, rt
inst_match = {'add': format1,
'sub': format2}
instruction_storage = [('add 9 0 255', 'string1'),
('sub 10 1 127', 'string2')]
for instruction in instruction_storage:
opline, string = instruction
opcode = opline.split()[0]
try:
inst_match[opcode](opline, string)
except KeyError:
print('unknown instruction: {!r}'.format(opcode))
输出:
format1('add90255','string1')
格式2('sub 10 1 127','string2')
我不太清楚你到底想要什么,但这里有一个猜测:
def format1(opline, string):
print('format1({!r}, {!r})'.format(opline, string))
opline = opline.split(' ', 1)[1]
rd, rs, rt = opline.split()
return rd, rs, rt
def format2(opline, string):
print('format2({!r}, {!r})'.format(opline, string))
opline = opline.split(' ', 1)[1]
rd, rs, rt = opline.split()
return rd, rs, rt
inst_match = {'add': format1,
'sub': format2}
instruction_storage = [('add 9 0 255', 'string1'),
('sub 10 1 127', 'string2')]
for instruction in instruction_storage:
opline, string = instruction
opcode = opline.split()[0]
try:
inst_match[opcode](opline, string)
except KeyError:
print('unknown instruction: {!r}'.format(opcode))
输出:
format1('add90255','string1')
格式2('sub 10 1 127','string2')
也许只有我一个人,但我不明白这个问题。你能说清楚点吗?也许只是我,但我不明白这个问题。请你说清楚一点好吗?