python re.match（）未返回预期结果

我正在尝试使用re.match选择python字符串的一部分：

revenue = "Revenue;;Item,Johnver,Vanston,Danbree,Vansey,Mundyke;Tea,190,140,1926,14,143;Coffee,325,19,293,1491,162;Water,682,14,852,56,659;Milk,829,140,609,120,87;;Expenses;;Item,Johnver,Vanston,Danbree,Vansey,Mundyke;Tea,120,65,890,54,430;Coffee,300,10,23,802,235;Water,50,299,1290,12,145;Milk,67,254,89,129,76;;"
revenue = re.match(r"(?<=Revenue;;).*(?=;E)", file_content)
print(revenue)

因此，我假设我的python实现有问题，但是，我在python正则表达式文档中找不到任何帮助我的信息。使用python 2和python 3进行了尝试

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我可能做错了什么

使用

re.search

Ex:

import re

revenue = "Revenue;;Item,Johnver,Vanston,Danbree,Vansey,Mundyke;Tea,190,140,1926,14,143;Coffee,325,19,293,1491,162;Water,682,14,852,56,659;Milk,829,140,609,120,87;;Expenses;;Item,Johnver,Vanston,Danbree,Vansey,Mundyke;Tea,120,65,890,54,430;Coffee,300,10,23,802,235;Water,50,299,1290,12,145;Milk,67,254,89,129,76;;"
revenue = re.search(r"(?<=Revenue;;).*(?=;E)", revenue)
print(revenue.group())

Item,Johnver,Vanston,Danbree,Vansey,Mundyke;Tea,190,140,1926,14,143;Coffee,325,19,293,1491,162;Water,682,14,852,56,659;Milk,829,140,609,120,87;

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根据Python文档

重新匹配（模式、字符串、标志=0）

如果字符串的开头有零个或多个字符与 正则表达式模式，返回相应的匹配对象。 如果字符串与模式不匹配，则返回None；请注意 与零长度匹配不同

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因此，您可能应该使用

re.search

或

re.findall

re.match

从字符串的开头开始匹配，因此后面的查找

（？
Item,Johnver,Vanston,Danbree,Vansey,Mundyke;Tea,190,140,1926,14,143;Coffee,325,19,293,1491,162;Water,682,14,852,56,659;Milk,829,140,609,120,87;