Python 计算特定操作后经过的时间
我想计算两组相等的时间。我使用Python 计算特定操作后经过的时间,python,function,loops,time,Python,Function,Loops,Time,我想计算两组相等的时间。我使用time.time()计算时间。但每当我计算集合相等的时间时,它返回的时间为1520763846.19。我想计算两个集合相等并且必须执行一些下游操作的时间。如果有任何帮助,我们将不胜感激 dis\u cars和dis\u cars是两套 def cars_on_road(dis_cars,forbid_cars): if len(forbid_cars) > 0 and dis_cars == forbid_cars: time_cal
time.time()
计算时间。但每当我计算集合相等的时间时,它返回的时间为1520763846.19
。我想计算两个集合相等并且必须执行一些下游操作的时间。如果有任何帮助,我们将不胜感激
dis\u cars和dis\u cars
是两套
def cars_on_road(dis_cars,forbid_cars):
if len(forbid_cars) > 0 and dis_cars == forbid_cars:
time_calculate = time.time()
print "time_calculate" + str(time_calculate)
下面是使用
datetime
模块的一种方法
import time
from datetime import datetime
def time_check(dis_cars, forbid_cars):
if len(forbid_cars) > 0 and dis_cars == forbid_cars:
time_calculate = datetime.now()
return time_calculate
else:
return None
dis_cars = {'A', 'B', 'C'}
forbid_cars = {'C', 'B', 'A'}
check_time = time_check(dis_cars, forbid_cars)
time.sleep(3)
time_change_since_match = (datetime.now() - check_time).total_seconds()
# 3.000125
解释
- 函数应该
返回一个值,该值可以存储在变量中供以后使用。打印值不会将该值存储在内存中
- 稍后,您可以再次访问此变量,并使用
等方法返回以秒为单位的时差total_seconds()
def __init__(self):
self.last = time.time() #Initialization instant
def cars_on_road(self, dis_cars,forbid_cars):
if len(forbid_cars) > 0 and dis_cars == forbid_cars:
time_calculate = time.time() - self.last #Difference between self.last and the instant the sets became equal
print "time_calculate" + str(time_calculate)
self.last = time.time() #Do this if this method will be called again