Python 发生异常时停止线程

我有10个线程，问题是当出现异常时，

bye

将打印10次

我只想打印一次，然后终止所有线程。这个问题有什么解决办法吗

from threading import Thread
def printmsg(msg,threadNumber):
    while True:
        try:
            print 'this is your message %s -- Thread Number:%s'%(msg,threadNumber)
        except:
              exit('Bye')

for i in range(0,11):
    Thread(target=printmsg,args=('Hello Wrold',str(i))).start()

---

您可以在线程中设置一个标志。在主循环中，您可以连续地

join（）

所有线程，以等待它们消失，然后如果设置了标志，则打印一条消息

---

该标志甚至可以是异常的值…

尝试通过主线程连接所有子线程。在主线程中完成您的工作

from threading import Thread, Lock

stop = False
lock = Lock()

def printmsg(msg, threadNumber):
    global stop
    while True:
        try:
            if threadNumber in [3, 5, 7, 9]: # Something wrong happens
                raise NotImplementedError

            lock.acquire()
            if stop:
                lock.release()
                break
            print 'This is your message %s -- Thread Number: %s' % (msg, threadNumber)
            lock.release()
        except NotImplementedError:
            lock.acquire()
            if not stop:
                stop = True
                print 'Bye'
            lock.release()
            break

for i in range(0,11):
    Thread(target=printmsg, args=('Hello World', i)).start()

#-*-coding:utf-8-*-

from threading import Thread

def printmsg(msg,threadNumber):
    while True:
        try:
            print 'this is your message %s -- Thread Number:%s'%(msg,threadNumber)
            raise
        except:
            break

if __name__ == '__main__':
    threads = []
    for i in range(0,11):
        threads.append(Thread(target=printmsg,args=('Hello Wrold',str(i))))
    for t in threads:
        t.start()
    for t in threads:
        t.join()
    exit('Bye')

---

示例代码中的语法错误是为了引发异常吗？好吧，您已经在这段时间内修复了它。顺便说一下，您正在启动11个线程，而不是10个。检查你的间隔逻辑。