MapReduce 2键减缩器-Python

这应该很简单，我已经花了几个小时在这上面

示例数据（名称、二进制、计数）：

所需的示例输出（名称、二进制、计数）：

每个名称都需要有自己的二进制键0或1。基于二进制键，对count列求和。请注意所需输出中的“reduce”

我已经提供了我的一些代码，我正在尝试在reducer中不使用列表或字典来执行

“”“ Reducer将名称与二进制文件结合起来，并对其进行部分计数

输入： 名称\t二进制\t计数

输出： 名称\t二进制\t计数
“”“

由于某些原因，它无法正确打印。（通过的第一个名字是funky）我也不确定最好的方法是通过一个计数和零个计数（也显示二进制标签）的所有打印

---

任何帮助都将不胜感激。谢谢

我认为最好使用熊猫图书馆

import pandas as pd
from io import StringIO
a ="""Adam 0 1
Adam 1 1
Adam 0 1
Mike 1 1
Mike 0 1
Mike 1 1"""

text = StringIO(a)
name, binary, count = [],[],[]

for line in text.readlines():
    a = line.strip().split(" ")
    name.append(a[0])
    binary.append(a[1])
    count.append(a[2])

df = pd.DataFrame({'name': name, "binary": binary, "count": count})
df['count'] = df['count'].astype(int)
df = df.groupby(['name', 'binary'])['count'].sum().reset_index()
print(df)
name    binary  count
0   Adam    0   2
1   Adam    1   1
2   Mike    0   1
3   Mike    1   2

如果您的数据已存在于csv或文本文件中。它可以用熊猫来读

df = pd.read_csv('path to your file')

---

压痕不好，情况处理不当

import re
import sys

current_name = None
zero_count, one_count = 0,0
i = 0
for line in sys.stdin:
    # parse the input
    name, binary, count = line.split('\t')
    #print(name)
    #print(current_name)
    if(i == 0):
        current_name = name
        i  = i + 1
    if(name == current_name):
        if int(binary) == 0:
            zero_count += int(count)

        elif int(binary) == 1:
            one_count += int(count)
    else:
        print(f'{current_name}\t{0} \t{zero_count}')
        print(f'{current_name}\t{1} \t{one_count}')
        current_name = name
        #print(current_name)
        zero_count, one_count = 0,0
        if int(binary) == 0:
            zero_count += int(count)
        elif int(binary) == 1:
            one_count += int(count)
print(f'{current_name}\t{0} \t{zero_count}')
print(f'{current_name}\t{1} \t{one_count}')

“i”处理第一行输入没有“当前名称”的情况（它只运行一次）。
在else块中，您必须重新初始化“zero\u count”和“one\u count”，并对新的“current\u name”进行计算

我的代码的输出：

Adam    0       2
Adam    1       1
Mike    0       1
Mike    1       2

---

我认为OP想要使用Hadoop

df = pd.read_csv('path to your file')

import re
import sys

current_name = None
zero_count, one_count = 0,0
i = 0
for line in sys.stdin:
    # parse the input
    name, binary, count = line.split('\t')
    #print(name)
    #print(current_name)
    if(i == 0):
        current_name = name
        i  = i + 1
    if(name == current_name):
        if int(binary) == 0:
            zero_count += int(count)

        elif int(binary) == 1:
            one_count += int(count)
    else:
        print(f'{current_name}\t{0} \t{zero_count}')
        print(f'{current_name}\t{1} \t{one_count}')
        current_name = name
        #print(current_name)
        zero_count, one_count = 0,0
        if int(binary) == 0:
            zero_count += int(count)
        elif int(binary) == 1:
            one_count += int(count)
print(f'{current_name}\t{0} \t{zero_count}')
print(f'{current_name}\t{1} \t{one_count}')

Adam    0       2
Adam    1       1
Mike    0       1
Mike    1       2