Python 允许用户输入单词的列表位置，以返回列表中的第二个和第三个元素

我需要有人帮助我编写代码，而不使用外部库和异常计数器

lineList = [['Cat', 'c', 1, x],['Cat', 'a', 2, x],['Cat', 't', 3, x],['Bat', 'b', 1, 3],['Bat', 'b', 1, 2],['Mat', 'm', 1, 1],['Fat', 'f', 1, 13]]

2D列表中出现2次以上的单词将显示在数字列表中

例如：

如何允许用户通过输入列表位置编号来选择单词？例如，如果用户输入1，它将返回嵌套列表中Cat的第二个和第三个元素：

c = 1, a = 2, t = 3

我是Python的初学者，因此不确定如何处理此问题。

您可以使用、、和：

输出：

1. Cat
2. Bat

对于位于特定位置的字符串：

n = int(input('position: '))   #   1-indexed

print('{0}. {1}'.format(n, filtered[n - 1][0]))   #   0-indexed (hence, n - 1)

使用a数数单词，然后使用

枚举

为列表编号：

from collections import Counter

lineList = [['Cat', 'c', 1, 2],['Cat', 'c', 1, 3],['Bat', 'b', 1, 4],['Bat', 'b', 1, 3],['Bat', 'b', 1, 2],['Mat', 'm', 1, 1],['Fat', 'f', 1, 13]]

counts = Counter(word for word, *other_stuff in lineList)

filtered = [word for word, count in counts.items() if count >= 2]

for number, word in enumerate(filtered, start=1):
    print("{: >2}.".format(number), word)

印刷品

 1. Cat
 2. Bat

如果无法导入

计数器

，则可以非常轻松地编写基本替换：

def Counter(seq):
    d = {}
    for item in seq:
        d[item] = d.get(item, 0) + 1
    return d

（

计数器

有更多功能，但这就是我们使用的全部功能）

然后，您可以使用以下选项选择一个单词：

def choose(filtered):
    while True:
        choice = input("Select a word: ")
        try:
            choice = int(choice)
            return filtered[choice-1]
        except ValueError, IndexError:
            print("Please enter a number on the list")

---

就在这里，只需检查嵌套列表中第二项的值是否大于1

list1 = [['Cat', 2], ['Bat', 3], ['Fat', 1], ['Mat', 1]]

index = 1
for i in range(len(list1)):
    if list1[i][1] > 1:
        print (str(index)+ ". " + str(list1[i][0]))
        index += 1

这张照片是：

1. Cat
2. Bat

---

你把描述改了一点，所以我把答案改写得更合适

lineList = [['Cat', 'c', 1, 'x'],['Cat', 'a', 2, 'x'],['Cat', 't', 3, 'x'],['Bat', 'b', 1, 3],['Bat', 'b', 1, 2],['Mat', 'm', 1, 1],['Fat', 'f', 1, 13]]


#First we create a dictionary with the repeating words in the list you gave
nameList = []    
frequencyDict = {}
for i in range(len(lineList)):

    if lineList[i][0] in frequencyDict.keys():
        frequencyDict[lineList[i][0]] += 1
    else:
        frequencyDict[lineList[i][0]] = 1

    #this will give you a list with the order
    #it will be useful to get the indices of the repeating word later
    nameList.append(lineList[i][0]) 


# Printing a list of values when if they are repeated
index = 1
repeats = []
for i in frequencyDict.keys():

    if frequencyDict[i] > 1: #This if statement checks if it was repeated or not

        print(str(index)+ ". " + i)
        repeats.append(i) # we also crete yet another list so the user can call it with his input later
        index += 1



x = (int(input("Which item on the list would you like to know more information about: \n")) -1) #note that we are subtracting one from the input so it matches the index of the list

# Here I am trying to get all the indices that start with the word that user replied
indicesList = []
for i in range(len(nameList)):
    if nameList[i] == repeats[x]:
        indicesList.append(i)

# Here I am printing the value that is in the index 1 and 2 of the nested list in Linelist
for i in range(len(indicesList)):
    print(str(lineList[indicesList[i]][1]) +
        " = " +
        str(lineList[indicesList[i]][2]))

---

我如何允许用户通过输入列表位置号来选择一个单词，例如，如果用户输入1，它将返回Cat及其嵌套列表中的相应值，例如，“c”，1，2:）@gstar我刚刚用这个问题的解决方案更新了我的答案。@gstar您必须在我答案的第一个代码中定义它，

filtered=[p for p in word\u计数，如果p[1]>1]

。真是太棒了！唯一的问题是当我输入1时，它只返回cat。有没有一种方法可以让它从行列表返回所有其他元素，例如c、1和2，例如['Cat'，c'，1，2]@gstar如果用户输入

1

，您希望得到什么结果？因此，for循环中if语句中的值'i'是原始行列表的索引。使用那个索引号来获取原始列表的信息。我在不同的评论中回答了这个问题，因为现在问题的表述有点不同

1. Cat
2. Bat

lineList = [['Cat', 'c', 1, 'x'],['Cat', 'a', 2, 'x'],['Cat', 't', 3, 'x'],['Bat', 'b', 1, 3],['Bat', 'b', 1, 2],['Mat', 'm', 1, 1],['Fat', 'f', 1, 13]]


#First we create a dictionary with the repeating words in the list you gave
nameList = []    
frequencyDict = {}
for i in range(len(lineList)):

    if lineList[i][0] in frequencyDict.keys():
        frequencyDict[lineList[i][0]] += 1
    else:
        frequencyDict[lineList[i][0]] = 1

    #this will give you a list with the order
    #it will be useful to get the indices of the repeating word later
    nameList.append(lineList[i][0]) 


# Printing a list of values when if they are repeated
index = 1
repeats = []
for i in frequencyDict.keys():

    if frequencyDict[i] > 1: #This if statement checks if it was repeated or not

        print(str(index)+ ". " + i)
        repeats.append(i) # we also crete yet another list so the user can call it with his input later
        index += 1



x = (int(input("Which item on the list would you like to know more information about: \n")) -1) #note that we are subtracting one from the input so it matches the index of the list

# Here I am trying to get all the indices that start with the word that user replied
indicesList = []
for i in range(len(nameList)):
    if nameList[i] == repeats[x]:
        indicesList.append(i)

# Here I am printing the value that is in the index 1 and 2 of the nested list in Linelist
for i in range(len(indicesList)):
    print(str(lineList[indicesList[i]][1]) +
        " = " +
        str(lineList[indicesList[i]][2]))