R 如何将键/值字符串转换为单独的列?
我有一个R 如何将键/值字符串转换为单独的列?,r,split,multiple-columns,key-value,R,Split,Multiple Columns,Key Value,我有一个data.frame和key/value string列,其中包含一组用户的特征及其值的信息。大概是这样的: data<-data.frame(id=1:3,statid=c("s003e","s093u","s085t"),str=c("a:1,7:2","a:1,c:4","a:3,b:5,c:33")) data # id statid str # 1 1 s003e a:1,7:2 # 2 2 s093u a:1,c:4 #
data.frame
和key/value string
列,其中包含一组用户的特征及其值的信息。大概是这样的:
data<-data.frame(id=1:3,statid=c("s003e","s093u","s085t"),str=c("a:1,7:2","a:1,c:4","a:3,b:5,c:33"))
data
# id statid str
# 1 1 s003e a:1,7:2
# 2 2 s093u a:1,c:4
# 3 3 s085t a:3,b:5,c:33
data您可以使用dplyr
和tidyr
:
library(dplyr); library(tidyr)
data %>% mutate(str = strsplit(str, ",")) %>% unnest(str) %>%
separate(str, into = c('var', 'val'), sep = ":") %>% spread(var, val, fill = 0)
# id statid 7 a b c
# 1 1 s003e 2 1 0 0
# 2 2 s093u 0 1 0 4
# 3 3 s085t 0 3 5 33
我们可以使用cSplit
以更干净的方式完成这项工作。通过在,
处拆分,将数据转换为“长”格式,然后在:
和dcast
处将数据从“长”拆分为“宽”
library(splitstackshape)
library(data.table)
dcast(cSplit(cSplit(data, "str", ",", "long"), "str", ":"),
id+statid~str_1, value.var="str_2", fill = 0)
# id statid 7 a b c
#1: 1 s003e 2 1 0 0
#2: 2 s093u 0 1 0 4
#3: 3 s085t 0 3 5 33
请参见splitstackshape
package。
library(splitstackshape)
library(data.table)
dcast(cSplit(cSplit(data, "str", ",", "long"), "str", ":"),
id+statid~str_1, value.var="str_2", fill = 0)
# id statid 7 a b c
#1: 1 s003e 2 1 0 0
#2: 2 s093u 0 1 0 4
#3: 3 s085t 0 3 5 33