如何去除R中的na并使下面的值上升
我有一个如下所示的数据框: 我如何删除na并使用下面的值向上 谢谢如何去除R中的na并使下面的值上升,r,reshape,R,Reshape,我有一个如下所示的数据框: 我如何删除na并使用下面的值向上 谢谢 id name.america name.europe name.asia 1 a <NA> <NA> 2 <NA> b <NA> 3 <NA> <NA> c 4 d
id name.america name.europe name.asia
1 a <NA> <NA>
2 <NA> b <NA>
3 <NA> <NA> c
4 d <NA> <NA>
我们可以循环遍历列并删除
NA
,然后在获得list
元素的max
长度后,通过在末尾添加NA
使list
元素的长度相同。在此基础上,对数据集的“id”列进行子集,并与输出一起追加
lst <- lapply(df1[-1], na.omit)
lst1 <- lapply(lst, `length<-`, max(lengths(lst)))
out <- data.frame(lst1)
out1 <- cbind(id = df1$id[seq_len(nrow(out))], out)
out1
# id name.america name.europe name.asia
#1 1 a b c
#2 2 d <NA> <NA>
数据
基于df1[,-1]的解决方案
require(tidyverse)
df1 %>%
gather(key = "name", value = "val", -id) %>%
na.omit() %>%
select(-id) %>%
group_by(name) %>%
mutate(id = 1:n()) %>%
spread(key = name, value = val)
结果
您的数据是如何以这种格式结束的?为id=2取一个值,然后将其移动到id=1,感觉很奇怪。Id应该是您的标识符
out1[is.na(out1)] <- ""
df1 <- structure(list(id = 1:4, name.america = c("a", NA, NA, "d"),
name.europe = c(NA, "b", NA, NA), name.asia = c(NA, NA, "c",
NA)), class = "data.frame", row.names = c(NA, -4L))
df1[, -1] <- lapply(df1[,-1], function(x) c(na.omit(x), rep("",length(x)-length(na.omit(x)))))
df1[1:max(colSums(!(df1[,-1]==""))),]
# id name.america name.europe name.asia
#1 1 a b c
#2 2 d
require(tidyverse)
df1 %>%
gather(key = "name", value = "val", -id) %>%
na.omit() %>%
select(-id) %>%
group_by(name) %>%
mutate(id = 1:n()) %>%
spread(key = name, value = val)
# A tibble: 2 x 4
id name.america name.asia name.europe
<int> <chr> <chr> <chr>
1 1 a c b
2 2 d NA NA
df1 <- structure(
list(
id = 1:4,
name.america = c("a", NA, NA, "d"),
name.europe = c(NA, "b", NA, NA),
name.asia = c(NA, NA, "c",
NA)
),
class = "data.frame",
row.names = c(NA, -4L)
)