“如何修复”;“$<;-”中出现错误。data.frame`replacement有x行,data有y";?
我的目标是创建一个for循环,将数据集中的某些特定列转换为因子或整数 条件将基于列的名称“如何修复”;“$<;-”中出现错误。data.frame`replacement有x行,data有y";?,r,R,我的目标是创建一个for循环,将数据集中的某些特定列转换为因子或整数 条件将基于列的名称 # Here is a small reproducible dataset df <- data.frame(x = c(10,20,30), y = c("yes", "no", "no"), z = c("Big", "Small", "Average")) # here is a vector that we are going to use inside our if statement
# Here is a small reproducible dataset
df <- data.frame(x = c(10,20,30), y = c("yes", "no", "no"), z = c("Big", "Small", "Average"))
# here is a vector that we are going to use inside our if statement
column_factor_names <- c("y", "z")
# for each column in df
for (i in names(df)) {
print(i)
# if it's a factor, convert into factor, else convert it into integer
if (i %in% column_factor_names) {
print("it's a factor")
df$i <- as.factor(df$i)
} else {
print("it's an integer")
df$i <- as.integer(df$i)
}
}
我的问题是:为什么它在for循环和if语句中不起作用?在代码中,子集函数
$
查找名为i
的列,而不是计算i
。您可以选择使用[,i]
或[[i]]
对data.frame进行不同的子集划分:
x <- data.frame(x = c(10,20,30), y = c("yes", "no", "no"), z = c("Big", "Small", "Average"))
# here is a vector that we are going to use inside our if statement
column_factor_names <- c("y", "z")
# for each column in df
for (i in names(df)) {
print(i)
# if it's a factor, convert into factor, else convert it into integer
if (i %in% column_factor_names) {
print("it's a factor")
x[[i]] <- as.factor(x[[i]])
} else {
print("it's an integer")
x[[i]] <- as.integer(x[[i]])
}
}
循环部分的正确代码为:
# Here is a small reproducible dataset
df <- data.frame(x = c(10,20,30), y = c("yes", "no", "no"), z = c("Big", "Small", "Average"))
# here is a vector that we are going to use inside our if statement
column_factor_names <- c("y", "z")
for (i in names(df)) {
print(i)
if (i %in% column_factor_names) {
print("it's a factor")
df[,i] <- as.factor(df[,i])
} else {
print("it's an integer")
df[,i] <- as.numeric(df[,i])
}
}
#这是一个可复制的小数据集
df请参阅帮助(“$”
。无需forloop
,相关的,可能重复的
x <- data.frame(x = c(10,20,30), y = c("yes", "no", "no"), z = c("Big", "Small", "Average"))
# here is a vector that we are going to use inside our if statement
column_factor_names <- c("y", "z")
# for each column in df
for (i in names(df)) {
print(i)
# if it's a factor, convert into factor, else convert it into integer
if (i %in% column_factor_names) {
print("it's a factor")
x[[i]] <- as.factor(x[[i]])
} else {
print("it's an integer")
x[[i]] <- as.integer(x[[i]])
}
}
x[, i] <- as.factor(x[, i])
# Here is a small reproducible dataset
df <- data.frame(x = c(10,20,30), y = c("yes", "no", "no"), z = c("Big", "Small", "Average"))
# here is a vector that we are going to use inside our if statement
column_factor_names <- c("y", "z")
for (i in names(df)) {
print(i)
if (i %in% column_factor_names) {
print("it's a factor")
df[,i] <- as.factor(df[,i])
} else {
print("it's an integer")
df[,i] <- as.numeric(df[,i])
}
}