R 根据条件从另一列向列赋值
假设我有这样一个列表:R 根据条件从另一列向列赋值,r,R,假设我有这样一个列表: > desired <- c("10001", "10004") > desired_sample_df <- data.frame(geo = rep("other", 30), zip = c(rep(10001:10010, 2), 10011:10020), cbsa = c(rep("NY", 20), rep("CA", 10))) > desired_sample_df geo zip cbsa 1 other
> desired <- c("10001", "10004")
> desired_sample_df <- data.frame(geo = rep("other", 30), zip = c(rep(10001:10010, 2), 10011:10020), cbsa = c(rep("NY", 20), rep("CA", 10)))
> desired_sample_df
geo zip cbsa
1 other 10001 NY
2 other 10002 NY
3 other 10003 NY
4 other 10004 NY
5 other 10005 NY
6 other 10006 NY
7 other 10007 NY
8 other 10008 NY
9 other 10009 NY
10 other 10010 NY
11 other 10001 NY
12 other 10002 NY
13 other 10003 NY
14 other 10004 NY
15 other 10005 NY
16 other 10006 NY
17 other 10007 NY
18 other 10008 NY
19 other 10009 NY
20 other 10010 NY
21 other 10011 CA
22 other 10012 CA
23 other 10013 CA
24 other 10014 CA
25 other 10015 CA
26 other 10016 CA
27 other 10017 CA
28 other 10018 CA
29 other 10019 CA
30 other 10020 CA
问题之一是数据帧中的字符串会自动成为因素。试试这个:
desired <- c("10001", "10004")
df <- data.frame(geo = rep("other", 30), zip = c(rep(10001:10010, 2), 10011:10020), cbsa = c(rep("NY", 20), rep("CA", 10)), stringsAsFactors=FALSE)
idx <- df$zip %in% desired
desired问题之一是数据帧中的字符串自动成为因素。试试这个:
desired <- c("10001", "10004")
df <- data.frame(geo = rep("other", 30), zip = c(rep(10001:10010, 2), 10011:10020), cbsa = c(rep("NY", 20), rep("CA", 10)), stringsAsFactors=FALSE)
idx <- df$zip %in% desired
desired问题之一是数据帧中的字符串自动成为因素。试试这个:
desired <- c("10001", "10004")
df <- data.frame(geo = rep("other", 30), zip = c(rep(10001:10010, 2), 10011:10020), cbsa = c(rep("NY", 20), rep("CA", 10)), stringsAsFactors=FALSE)
idx <- df$zip %in% desired
desired问题之一是数据帧中的字符串自动成为因素。试试这个:
desired <- c("10001", "10004")
df <- data.frame(geo = rep("other", 30), zip = c(rep(10001:10010, 2), 10011:10020), cbsa = c(rep("NY", 20), rep("CA", 10)), stringsAsFactors=FALSE)
idx <- df$zip %in% desired
希望像这样
df$geo <- ifelse(df$zip %in% desired,df$zip,df$geo)
df$geo像这样
df$geo <- ifelse(df$zip %in% desired,df$zip,df$geo)
df$geo像这样
df$geo <- ifelse(df$zip %in% desired,df$zip,df$geo)
df$geo像这样
df$geo <- ifelse(df$zip %in% desired,df$zip,df$geo)
df$geo我添加了stringsAsFactors=FALSE
部分,因为它给了您错误。啊,这是有道理的。不确定是什么导致了错误。不知道如何给答案排序,但为了简洁起见,我把它交给了@jhoward……你只能接受一个答案,不幸的是没有银牌;-)我添加了stringsAsFactors=FALSE
部分,因为它会给您带来错误。啊,这是有道理的。不确定是什么导致了错误。不知道如何给答案排序,但为了简洁起见,我把它交给了@jhoward……你只能接受一个答案,不幸的是没有银牌;-)我添加了stringsAsFactors=FALSE
部分,因为它会给您带来错误。啊,这是有道理的。不确定是什么导致了错误。不知道如何给答案排序,但为了简洁起见,我把它交给了@jhoward……你只能接受一个答案,不幸的是没有银牌;-)我添加了stringsAsFactors=FALSE
部分,因为它会给您带来错误。啊,这是有道理的。不确定是什么导致了错误。不知道如何给答案排序,但为了简洁起见,我把它交给了@jhoward……你只能接受一个答案,不幸的是没有银牌;-)