R 在条形图中对X轴进行排序
我将数据分为以下几类:R 在条形图中对X轴进行排序,r,statistics,R,Statistics,我将数据分为以下几类: (8.048,18.05] (-21.95,-11.95] (-31.95,-21.95] (18.05,28.05] (-41.95,-31.95] 81 76 18 18 12 (-132,-122] (-122,-112] (-112,-102] (-162,-152] (-102,-91.95]
(8.048,18.05] (-21.95,-11.95] (-31.95,-21.95] (18.05,28.05] (-41.95,-31.95]
81 76 18 18 12
(-132,-122] (-122,-112] (-112,-102] (-162,-152] (-102,-91.95]
6 6 6 5 5
(-91.95,-81.95] (-192,-182] (28.05,38.05] (38.05,48.05] (58.05,68.05]
5 4 4 4 4
(78.05,88.05] (98.05,108] (-562,-552] (-512,-502] (-482,-472]
4 4 3 3 3
(-452,-442] (-412,-402] (-282,-272] (-152,-142] (48.05,58.05]
3 3 3 3 3
(68.05,78.05] (118,128] (128,138] (-582,-572] (-552,-542]
3 3 3 2 2
(-532,-522] (-422,-412] (-392,-382] (-362,-352] (-262,-252]
2 2 2 2 2
(-252,-242] (-142,-132] (-81.95,-71.95] (148,158] (-1402,-1392]
2 2 2 2 1
(-1372,-1362] (-1342,-1332] (-942,-932] (-862,-852] (-822,-812]
1 1 1 1 1
(-712,-702] (-682,-672] (-672,-662] (-632,-622] (-542,-532]
1 1 1 1 1
(-502,-492] (-492,-482] (-472,-462] (-462,-452] (-442,-432]
1 1 1 1 1
(-432,-422] (-352,-342] (-332,-322] (-312,-302] (-302,-292]
1 1 1 1 1
(-202,-192] (-182,-172] (-172,-162] (-51.95,-41.95] (88.05,98.05]
1 1 1 1 1
(108,118] (158,168] (168,178] (178,188] (298,308]
1 1 1 1 1
(318,328] (328,338] (338,348] (368,378] (458,468]
1 1 1 1 1
如何绘制这些数据,使垃圾箱从左侧最负的位置排序到右侧最正的位置?目前我的图表看起来像。请注意,它根本没有排序。特别是,第二条(value=76
)位于第一条的右侧:
(8.048,18.05] (-21.95,-11.95]
81 76
这是我用来绘图的命令:
barplot(x,ylab="Number of Unique Tags", xlab="Expected - Observed")
我真的很想帮你回答你的问题,但我得告诉你,我无法理解你的数据。我看到很多开始的括号,但没有结束的。数据按每行底部的值降序排列。我不知道如何利用“8.048,18.05”这样的值 我遗漏了一些明显的东西吗?你能举一个更简单的例子说明你的数据结构不是一个因素吗 我通常希望数据帧或矩阵有两列,一列代表X,一列代表Y 看看这个排序的例子是否有帮助(我这里有点像在黑暗中拍摄)
tN他使用的是通用数学范围表示法,[]是闭合区间,()是开放区间。所以对于他的第一个bin:(8.048,18.05]=81,这意味着对于范围8.048
是。我们应该修改杰夫的博文,说:“尊重原作者,或者尊重认为自己知道原作者想要什么的编辑;或者尊重不喜欢你的修改的编辑,以及原作者对你修改的批准。”。“我也有同样的问题。有人知道如何订购垃圾箱吗?根据FryGuy的评论,垃圾箱是一种数学符号,可以在R中使用“cut”或“cut2”轻松创建。”.像neversaint一样,我尝试在我的x轴上订购这些。当箱子都是正数时,订购会正确进行。但如果一个箱子的编号为负数,则不会如此!–WGray 6分钟前
tN <- table(Ni <- rpois(100, lambda=5))
r <- barplot(tN)
#stop here and examine the plot
#the next bit converts the matrix to a data frame,
# sorts it, and plots it again
df<-data.frame(tN)
df2<-df[order(df$Freq),]
barplot(df2$Freq)