如何grep R中的特定整数？

如何grep R中的特定整数？我认为参数

fixed=TRUE

允许这样做，但显然不是这样：

NameDataTable = "LONG_TE_B.xpt"
NDie = 1
DataTable = read.xport(NameDataTable)
pos_DataTable_Die = grep(as.character(NDie), DataTable[,"DIEINDEX"], fixed=TRUE)
DataTableDie = DataTable[pos_DataTable_Die,]

这也需要DIEINDEX等于11的行。这对我来说是个问题：

> DataTableDie[947, "DIEINDEX"]

[1] 一,

[1] 十一,

请问我怎么结算？先谢谢你

---

William

我们可以更具体地粘贴

和
$
。或者使用单词边界（
\\b
）

好的，行了！我只是：

DataTable = read.xport(NameDataTable)
for(i in 1:nrow(DataTable)){
  DataTable[i,"DIEINDEX"] = paste0("^",as.character(DataTable[i,"DIEINDEX"]),"$")
}
pos_DataTable_Die = grep(paste0("^",as.character(NDie),"$"), DataTable[,"DIEINDEX"], fixed=TRUE)
DataTableDie = DataTable[pos_DataTable_Die,]

为了可读性和整洁的工作流程，可能值得考虑软件包提供的解决方案：

as.numeirc（）
不会造成任何困难

str_detect(string = 1, pattern = vals)
[1]  TRUE FALSE FALSE

DataTable = read.xport(NameDataTable)
for(i in 1:nrow(DataTable)){
  DataTable[i,"DIEINDEX"] = paste0("^",as.character(DataTable[i,"DIEINDEX"]),"$")
}
pos_DataTable_Die = grep(paste0("^",as.character(NDie),"$"), DataTable[,"DIEINDEX"], fixed=TRUE)
DataTableDie = DataTable[pos_DataTable_Die,]

vals <- c("1", "11a", "DIEINDEX")
require(stringr)
str_detect(string = "1", pattern = vals)

> str_detect(string = "1", pattern = vals)
[1]  TRUE FALSE FALSE

str_detect(string = 1, pattern = vals)
[1]  TRUE FALSE FALSE