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如何从R中的列表创建多个矩阵或数据帧?_R_List_Dataframe_Matrix - Fatal编程技术网

如何从R中的列表创建多个矩阵或数据帧?

如何从R中的列表创建多个矩阵或数据帧?,r,list,dataframe,matrix,R,List,Dataframe,Matrix,我有这样一份清单: [[1]] [1] "Vigia" "PA" "1508209" [4] "Viseu" "PA" "1508308" [[2]] [1] "Abaetetuba" "PA"

我有这样一份清单:

[[1]]
[1] "Vigia"                      "PA"                         "1508209"                   
[4] "Viseu"                      "PA"                         "1508308"                   

[[2]]
[1] "Abaetetuba"                 "PA"                         "1500107"                   
[4] "Acara"                      "PA"                         "1500206"
                           [,1]                       [,2]                          [,3] 
[1,]                      Vigia                         PA                       1508209
[2,]                      Viseu                         PA                       1508308

                           [,1]                       [,2]                          [,3] 
[1,]                 Abaetetuba                         PA                       1500107
[2,]                      Acara                         PA                       1508308
我想做两个这样的矩阵:

[[1]]
[1] "Vigia"                      "PA"                         "1508209"                   
[4] "Viseu"                      "PA"                         "1508308"                   

[[2]]
[1] "Abaetetuba"                 "PA"                         "1500107"                   
[4] "Acara"                      "PA"                         "1500206"
                           [,1]                       [,2]                          [,3] 
[1,]                      Vigia                         PA                       1508209
[2,]                      Viseu                         PA                       1508308

                           [,1]                       [,2]                          [,3] 
[1,]                 Abaetetuba                         PA                       1500107
[2,]                      Acara                         PA                       1508308
我试着用

for(i in 1:2){
  output[i] <- matrix(unlist(A[[i]]), ncol = 3, byrow = TRUE)
}
for(1:2中的i){
输出[i]编辑:
更正了我的答案,因此它使用了一个循环:

li <- list(c( "Vigia", "PA", "1508209", "Viseu", "PA", "1508308"),
           c("Abaetetuba", "PA", "1500107", "Acara", "PA", "1500206"))

output <- list()
for(i in seq_along(li)){
  output[[i]] <- matrix(li[[i]], nrow=2, byrow = TRUE)
}

output[[1]]

但是我们必须意识到矩阵只能有一种数据类型,这意味着在这种情况下,一切都将是一个字符串!

请共享
dput(head(your_list,2))
lappy(a,function(x)matrix(x,ncol=3,byrow=TRUE))
?几乎就是这样!但我想转换每个a[[I]]进入矩阵,在列表之外。我怎么做?
     [,1]         [,2] [,3]     
[1,] "Abaetetuba" "PA" "1500107"
[2,] "Acara"      "PA" "1500206"