R 如何将当前行的负值转移到数据帧中的前一行?
我想通过将当前行的负值添加到每个组中的前一行,将它们转移到前一行。 以下是我拥有的原始数据样本:R 如何将当前行的负值转移到数据帧中的前一行?,r,dataframe,dplyr,data.table,data-cleaning,R,Dataframe,Dplyr,Data.table,Data Cleaning,我想通过将当前行的负值添加到每个组中的前一行,将它们转移到前一行。 以下是我拥有的原始数据样本: raw_data <- data.frame(GROUP = rep(c('A','B','C'),each = 6), YEARMO = rep(c(201801:201806),3), VALUE = c(100,-10,20,70,-50,30,20,60,40,-20,-10,50,0,10,-30,50,10
raw_data <- data.frame(GROUP = rep(c('A','B','C'),each = 6),
YEARMO = rep(c(201801:201806),3),
VALUE = c(100,-10,20,70,-50,30,20,60,40,-20,-10,50,0,10,-30,50,100,-100))
> raw_data
GROUP YEARMO VALUE
1 A 201801 100
2 A 201802 -10
3 A 201803 20
4 A 201804 70
5 A 201805 -50
6 A 201806 30
7 B 201801 20
8 B 201802 60
9 B 201803 40
10 B 201804 -20
11 B 201805 -10
12 B 201806 50
13 C 201801 0
14 C 201802 10
15 C 201803 -30
16 C 201804 50
17 C 201805 100
18 C 201806 -100
原始数据原始数据
组值
1A 20180100
2 A 201802-10
3 A 201803 20
4 A 201804 70
5 A 201805-50
6 A 201806 30
7 B 201801 20
8 B 201802 60
9 B 201803 40
10 B 201804-20
11 B 201805-10
12 B 201806 50
13 C 201801 0
14 C 201802 10
15 C 201803-30
16 C 201804 50
17 C 201805 100
18 C 201806-100
以下是我想要的输出:
final_data <- data.frame(GROUP = rep(c('A','B','C'),each = 6),
YEARMO = rep(c(201801:201806),3),
VALUE = c(90,0,20,20,0,30,20,60,10,0,0,50,-20,0,0,50,0,0))
> final_data
GROUP YEARMO VALUE
1 A 201801 90
2 A 201802 0
3 A 201803 20
4 A 201804 20
5 A 201805 0
6 A 201806 30
7 B 201801 20
8 B 201802 60
9 B 201803 10
10 B 201804 0
11 B 201805 0
12 B 201806 50
13 C 201801 -20
14 C 201802 0
15 C 201803 0
16 C 201804 50
17 C 201805 0
18 C 201806 0
final_数据final_数据
组值
1A 201801 90
2 A 201802 0
3 A 201803 20
4 A 201804 20
5 A 201805 0
6 A 201806 30
7 B 201801 20
8 B 201802 60
9 B 201803 10
10 B 201804 0
11 B 201805 0
12 B 201806 50
13 C 201801-20
14 C 201802 0
15 C 201803 0
16 C 201804 50
17 C 201805 0
18 C 201806 0
以下数据框将显示如何在每个组中进行转换:
Trans_GRP_A <- data.frame(GROUP = rep('A',each = 6),
YEARMO = c(201801:201806),
VALUE = c(100,-10,20,70,-50,30),
ITER_1 = c(100,-10,20,20,0,30),
ITER_2 = c(90,0,20,20,0,30))
> Trans_GRP_A
GROUP YEARMO VALUE ITER_1 ITER_2
1 A 201801 100 100 90
2 A 201802 -10 -10 0
3 A 201803 20 20 20
4 A 201804 70 20 20
5 A 201805 -50 0 0
6 A 201806 30 30 30
> Trans_GRP_B <- data.frame(GROUP = rep('B',each = 6),
+ YEARMO = c(201801:201806),
+ VALUE = c(20,60,40,-20,-10,50),
+ ITER_1 = c(20,60,40,-30,0,50),
+ ITER_2 = c(20,60,10,0,0,50))
> Trans_GRP_B
GROUP YEARMO VALUE ITER_1 ITER_2
1 B 201801 20 20 20
2 B 201802 60 60 60
3 B 201803 40 40 10
4 B 201804 -20 -30 0
5 B 201805 -10 0 0
6 B 201806 50 50 50
> Trans_GRP_C <- data.frame(GROUP = rep('C',each = 6),
+ YEARMO = c(201801:201806),
+ VALUE = c(0,10,-30,50,100,-100),
+ ITER_1 = c(0,10,-30,50,0,0),
+ ITER_2 = c(0,-20,0,50,0,0),
+ ITER_3 = c(-20,0,0,50,0,0))
> Trans_GRP_C
GROUP YEARMO VALUE ITER_1 ITER_2 ITER_3
1 C 201801 0 0 0 -20
2 C 201802 10 10 -20 0
3 C 201803 -30 -30 0 0
4 C 201804 50 50 50 50
5 C 201805 100 0 0 0
6 C 201806 -100 0 0 0
library(data.table)
DT <- as.data.table(raw_data)
DT$final <- final_data$VALUE
DT[, new := {
x <- VALUE
sn <- 0
for (i in .N:1) {
if (i > 1) {
if (x[i] < 0) {
sn <- sn + x[i]
x[i] <- 0
} else {
tmp <- pmax(x[i] + sn, 0)
sn <- sn + x[i] - tmp
x[i] <- tmp
}
} else {
x[i] <- x[i] + sn
}
}
x
}, by = GROUP]
DT[]
Trans\u GRP\u A Trans\u GRP\u A
国际热核聚变1号国际热核聚变2号
1A 20180110090
2 A 201802-10-10 0
3 A 201803 20 20
4 A 201804 70 20 20
5 A 201805-50 0
6 A 201806 30 30 30
>Trans_GRP_B Trans_GRP_B
国际热核聚变1号国际热核聚变2号
1 B 201801 20 20
2 B 201802 60
3 B 201803 40 10
4 B 201804-20-30 0
5 B 201805-10 0 0
6 B 201806 50 50
>Trans_GRP_C Trans_GRP_C
国际热核聚变1号国际热核聚变2号国际热核聚变3号
1 C 201801 0-20
2 C 201802 10 10-20 0
3 C 201803-30-30 0
4 C 201804 50 50
5 C 2018051000
6 C 201806-100 0
传输逻辑如下所示:
欢迎任何解决办法。我认为矢量化的解决方案可能执行得更快。这是一个棘手的问题。我试图找到一个矢量化的解决方案,但到目前为止唯一有效的方法是向后循环每个组内的行:
Trans_GRP_A <- data.frame(GROUP = rep('A',each = 6),
YEARMO = c(201801:201806),
VALUE = c(100,-10,20,70,-50,30),
ITER_1 = c(100,-10,20,20,0,30),
ITER_2 = c(90,0,20,20,0,30))
> Trans_GRP_A
GROUP YEARMO VALUE ITER_1 ITER_2
1 A 201801 100 100 90
2 A 201802 -10 -10 0
3 A 201803 20 20 20
4 A 201804 70 20 20
5 A 201805 -50 0 0
6 A 201806 30 30 30
> Trans_GRP_B <- data.frame(GROUP = rep('B',each = 6),
+ YEARMO = c(201801:201806),
+ VALUE = c(20,60,40,-20,-10,50),
+ ITER_1 = c(20,60,40,-30,0,50),
+ ITER_2 = c(20,60,10,0,0,50))
> Trans_GRP_B
GROUP YEARMO VALUE ITER_1 ITER_2
1 B 201801 20 20 20
2 B 201802 60 60 60
3 B 201803 40 40 10
4 B 201804 -20 -30 0
5 B 201805 -10 0 0
6 B 201806 50 50 50
> Trans_GRP_C <- data.frame(GROUP = rep('C',each = 6),
+ YEARMO = c(201801:201806),
+ VALUE = c(0,10,-30,50,100,-100),
+ ITER_1 = c(0,10,-30,50,0,0),
+ ITER_2 = c(0,-20,0,50,0,0),
+ ITER_3 = c(-20,0,0,50,0,0))
> Trans_GRP_C
GROUP YEARMO VALUE ITER_1 ITER_2 ITER_3
1 C 201801 0 0 0 -20
2 C 201802 10 10 -20 0
3 C 201803 -30 -30 0 0
4 C 201804 50 50 50 50
5 C 201805 100 0 0 0
6 C 201806 -100 0 0 0
library(data.table)
DT <- as.data.table(raw_data)
DT$final <- final_data$VALUE
DT[, new := {
x <- VALUE
sn <- 0
for (i in .N:1) {
if (i > 1) {
if (x[i] < 0) {
sn <- sn + x[i]
x[i] <- 0
} else {
tmp <- pmax(x[i] + sn, 0)
sn <- sn + x[i] - tmp
x[i] <- tmp
}
} else {
x[i] <- x[i] + sn
}
}
x
}, by = GROUP]
DT[]
sn
存储,即累加负值,然后由随后的(相反顺序)正值“消耗” 这里有另一个选项,可以递归地将向量的正部分与向量的负部分相加,直到没有更多的负值,或者已经执行了.N次(其中.N是每组的行数)
我怀疑是否存在一个纯粹的矢量化解决方案。可能需要一个循环构造
GROUP YEARMO VALUE OUTPUT
1: A 201801 100 90
2: A 201802 -10 0
3: A 201803 20 20
4: A 201804 70 20
5: A 201805 -50 0
6: A 201806 30 30
7: B 201801 20 20
8: B 201802 60 60
9: B 201803 40 10
10: B 201804 -20 0
11: B 201805 -10 0
12: B 201806 50 50
13: C 201801 0 -20
14: C 201802 10 0
15: C 201803 -30 0
16: C 201804 50 50
17: C 201805 100 0
18: C 201806 -100 0