R dplyr-按名称模式重新排列列

我得到了一些长格式的数据，1）需要重新调整为宽格式，然后2）需要根据列名称的模式重新设置列。示例数据如下：

#Orignial data
set.seed(100)
long_df <- tibble(id = rep(1:5, each = 3),
                  group = rep(c('g1','g2','g3'), times = 5),
                  mean = runif(15, min = 1, max = 10),
                  sd = runif(15, min = .025, max = 1))
long_df

# A tibble: 15 x 4
      id group  mean    sd
   <int> <chr> <dbl> <dbl>
 1     1 g1     3.77 0.677
 2     1 g2     3.32 0.224
 3     1 g3     5.97 0.374
 4     2 g1     1.51 0.375
 5     2 g2     5.22 0.698
 6     2 g3     5.35 0.547
 7     3 g1     8.31 0.718
 8     3 g2     4.33 0.550
 9     3 g3     5.92 0.755
10     4 g1     2.53 0.435
11     4 g2     6.62 0.192
12     4 g3     8.94 0.776
13     5 g1     3.52 0.885
14     5 g2     4.59 0.560
15     5 g3     7.86 0.296

#Reshaped to wide
wide_df <- long_df %>% 
  pivot_wider(id_cols = id, names_from = 'group', values_from = c('mean','sd'))
wide_df

# A tibble: 5 x 7
     id mean_g1 mean_g2 mean_g3 sd_g1 sd_g2 sd_g3
  <int>   <dbl>   <dbl>   <dbl> <dbl> <dbl> <dbl>
1     1    3.77    3.32    5.97 0.677 0.224 0.374
2     2    1.51    5.22    5.35 0.375 0.698 0.547
3     3    8.31    4.33    5.92 0.718 0.550 0.755
4     4    2.53    6.62    8.94 0.435 0.192 0.776
5     5    3.52    4.59    7.86 0.885 0.560 0.296

#Wide with proper column order
final_df <- wide_df %>% 
  select(id, mean_g1, sd_g1, mean_g2, sd_g2, mean_g3, sd_g3)
final_df

# A tibble: 5 x 7
     id mean_g1 sd_g1 mean_g2 sd_g2 mean_g3 sd_g3
  <int>   <dbl> <dbl>   <dbl> <dbl>   <dbl> <dbl>
1     1    3.77 0.677    3.32 0.224    5.97 0.374
2     2    1.51 0.375    5.22 0.698    5.35 0.547
3     3    8.31 0.718    4.33 0.550    5.92 0.755
4     4    2.53 0.435    6.62 0.192    8.94 0.776
5     5    3.52 0.885    4.59 0.560    7.86 0.296

原始数据 种子集（100）

---

long_df您可以在数字后缀的字符向量上连续运行

ends_with

：

long_df %>% 
  pivot_wider(names_from=group, values_from=c(mean, sd)) %>% 
  select(id, ends_with(as.character(1:3)))

id mean\u g1 sd\u g1 mean\u g2 sd\u g2 mean\u g3 sd\u g3
1     1    3.77 0.677    3.32 0.224    5.97 0.374
2     2    1.51 0.375    5.22 0.698    5.35 0.547
3     3    8.31 0.718    4.33 0.550    5.92 0.755
4     4    2.53 0.435    6.62 0.192    8.94 0.776
5     5    3.52 0.885    4.59 0.560    7.86 0.296

---

我的实际数据中的组没有连续排序，而是平均值，但第二个解决方案确实有效。我意识到我忘了添加一个额外的子组变量，但我能够调整代码，例如将pivot调整为最长，然后调整为所需的宽格式。非常感谢。

     id mean_g1 sd_g1 mean_g2 sd_g2 mean_g3 sd_g3
  <int>   <dbl> <dbl>   <dbl> <dbl>   <dbl> <dbl>
1     1    3.77 0.677    3.32 0.224    5.97 0.374
2     2    1.51 0.375    5.22 0.698    5.35 0.547
3     3    8.31 0.718    4.33 0.550    5.92 0.755
4     4    2.53 0.435    6.62 0.192    8.94 0.776
5     5    3.52 0.885    4.59 0.560    7.86 0.296

long_df %>% 
  pivot_longer(cols=c(mean, sd)) %>% 
  pivot_wider(names_from=c(name, group), values_from=value)

     id mean_g1 sd_g1 mean_g2 sd_g2 mean_g3 sd_g3
  <int>   <dbl> <dbl>   <dbl> <dbl>   <dbl> <dbl>
1     1    3.77 0.677    3.32 0.224    5.97 0.374
2     2    1.51 0.375    5.22 0.698    5.35 0.547
3     3    8.31 0.718    4.33 0.550    5.92 0.755
4     4    2.53 0.435    6.62 0.192    8.94 0.776
5     5    3.52 0.885    4.59 0.560    7.86 0.296