R 比较连续列单元格值并替换其他列值
我有一个如下所示的数据框,其中比较了R 比较连续列单元格值并替换其他列值,r,apply,R,Apply,我有一个如下所示的数据框,其中比较了lse列中的连续值。如果lse 0的值后跟1,我想将lse的结束日期与0值一起设置为NA 输入: END_DATE lse 2016-01-20 0 2015-08-16 1 预期产出: END_DATE lse NA 0 2015-08-16 1 我尝试了下面的代码,但它不工作,也没有抛出任何错误 for (i in length(loan_test1$lse)){
lse
列中的连续值。如果lse 0
的值后跟1
,我想将lse
的结束日期
与0
值一起设置为NA
输入:
END_DATE lse
2016-01-20 0
2015-08-16 1
预期产出:
END_DATE lse
NA 0
2015-08-16 1
我尝试了下面的代码,但它不工作,也没有抛出任何错误
for (i in length(loan_test1$lse)){
if (length(loan_test1$lse) == 0 & length(loan_test1$lse)+1 == 1) {
loan_test1$END_DATE[i] <- "NA"
}
}
for(长度为i(贷款测试1$lse)){
如果(长度(贷款测试1$lse)==0,长度(贷款测试1$lse)+1==1){
贷款测试1$END\u日期[i]library(lubridate)
图书馆(tidyverse)
df
library(lubridate)
library(tidyverse)
df <- data.frame(END_DATE = seq.Date(from = (today()-99),to = today(),by=1),lse = sample(c(0,1), 100, replace = TRUE))
df <- df %>% mutate(leadlse = lead(lse))
condition <- df$lse == 0 & df$leadlse ==1
df$END_DATE[condition] = NA
df <- df %>% select(-leadlse)
df
df <- data.frame(END_DATE = seq.Date(from = (today()-99),to = today(),by=1),lse = sample(c(0,1), 100, replace = TRUE))
df$END_DATE[(df$lse == 0 & lead(df$lse) == 1)] <- NA