R 将嵌套列表转换为单个数据帧或TIBLE

我有一个非常大的嵌套列表，我想把它做成一个平面数据框。我为列表的前两个元素创建了一个dput以快速复制/粘贴（很抱歉，在创建df后，我可以清理很多nonesense），我尝试了以下类似的问题，即关于将列表转换为df的问题，但由于某些原因，似乎没有一个与我的兼容

谢谢大家!

以下是前两个元素的dput-完整列表有数千个元素：

list(structure(list(first = structure(list(text = c("\n\tMenghe a'Nyam\n\t\n\n  \n\n  \n\n  \n\n  \n          
Position:\n  \n  Forward\n\n\n\n  6-5, 215lb (196cm, 97kg) \n  \n\n  \n\n  \n  \n  \n\n  School:     
Canisius\n\n\n\n\n\n  More player info\n\n\n\n\n\n"  , 
"\n\tMenghe a'Nyam\n\t\n\n  \n\n  \n\n  \n\n  \n  Position:\n  \n  Forward\n\n\n\n  6-5, 215lb 
(196cm, 97kg) \n  \n\n  \n\n  \n  \n  \n\n  School: Canisius\n\n\n\n\n\n  More player 
info\n\n\n\n\n\n"  , 
"\n\tMenghe a'Nyam\n\t\n\n  \n\n  \n\n  \n\n  \n  Position:\n  \n  Forward\n\n\n\n  6-5, 215lb 
(196cm, 97kg) \n  \n\n  \n\n  \n  \n  \n\n  School: Canisius\n\n\n\n\n\n  More player 
info\n\n\n\n\n\n"  
)), row.names = c(NA, -3L), class = c("tbl_df", "tbl", "data.frame"
)), second = structure(list(Season = c("2006-07", "2007-08", 
"Career"), name = c("menghe-anyam", "menghe-anyam", "menghe-anyam"
)), row.names = c(NA, -3L), class = "data.frame")), row.names = c(NA, 
-3L), class = c("tbl_df", "tbl", "data.frame")), structure(list(
first = structure(list(text = c("\n\tJordan Aaberg\n\t\n\n  \n\n  \n\n  \n\n  \n  Position:\n  \n  
Forward\n\n\n\n  6-9, 225lb (206cm, 102kg) \n  \n\n  Hometown: Rothsay, MN\n\n\n\n  \n\n  High 
School: Rothsay\n\n\n\n  \n  \n  \n\n  School: North Dakota State\n\n\n\n\n\n  More player 
info\n\n\n\n\n\n"  , 
"\n\tJordan Aaberg\n\t\n\n  \n\n  \n\n  \n\n  \n  Position:\n  \n  Forward\n\n\n\n  6-9, 225lb 
(206cm, 102kg) \n  \n\n  Hometown: Rothsay, MN\n\n\n\n  \n\n  High School: Rothsay\n\n\n\n  \n  \n  
\n\n  School: North Dakota State\n\n\n\n\n\n  More player info\n\n\n\n\n\n"  , 
"\n\tJordan Aaberg\n\t\n\n  \n\n  \n\n  \n\n  \n  Position:\n  \n  Forward\n\n\n\n  6-9, 225lb 
(206cm, 102kg) \n  \n\n  Hometown: Rothsay, MN\n\n\n\n  \n\n  High School: Rothsay\n\n\n\n  \n  \n  
\n\n  School: North Dakota State\n\n\n\n\n\n  More player info\n\n\n\n\n\n"  , 
"\n\tJordan Aaberg\n\t\n\n  \n\n  \n\n  \n\n  \n  Position:\n  \n  Forward\n\n\n\n  6-9, 225lb 
(206cm, 102kg) \n  \n\n  Hometown: Rothsay, MN\n\n\n\n  \n\n  High School: Rothsay\n\n\n\n  \n  \n  
\n\n  School: North Dakota State\n\n\n\n\n\n  More player info\n\n\n\n\n\n"  , 
"\n\tJordan Aaberg\n\t\n\n  \n\n  \n\n  \n\n  \n  Position:\n  \n  Forward\n\n\n\n  6-9, 225lb 
(206cm, 102kg) \n  \n\n  Hometown: Rothsay, MN\n\n\n\n  \n\n  High School: Rothsay\n\n\n\n  \n  \n  
\n\n  School: North Dakota State\n\n\n\n\n\n  More player info\n\n\n\n\n\n"  
)), row.names = c(NA, -5L), class = c("tbl_df", "tbl", "data.frame"
)), second = structure(list(Season = c("2009-10", "2011-12", 
"2012-13", "2013-14", "Career"), name = c("jordan-aaberg", 
"jordan-aaberg", "jordan-aaberg", "jordan-aaberg", "jordan-aaberg"
)), row.names = c(NA, -5L), class = "data.frame")), row.names = c(NA, 
-5L), class = c("tbl_df", "tbl", "data.frame")))

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要在一个数据帧中获取数据，可以使用：

newdata <- do.call(rbind, lapply(data, function(x) do.call(cbind, x)))

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我们可以只做

bind_行

library(dplyr)
data %>% bind_rows

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优雅的解决方案！非常感谢。它工作得很好。你能帮我解释一下map_df和map_dfr的区别吗？还有，do.call，这个函数到底在做什么？大多数情况下，它们的工作原理完全相同，因此在本例中，您也可以使用

map\u dfr

do.call

在数据帧列表上应用函数（

cbind

），并将它们组合成一个数据帧。谢谢。我将对这些电话进行一些研究，以便将其添加到我的学习中@RonakShah我非常感谢你！

library(dplyr)
data %>% bind_rows