R 映射函数中的第二个参数
我有一个像这样的tibble:R 映射函数中的第二个参数,r,dplyr,purrr,R,Dplyr,Purrr,我有一个像这样的tibble: uuu <- structure(list(Id = c("a", "b"), lists = list(c(1:2), c(100:103)) ), .Names = c("Id", "lists"), row.names = c(NA, 2L), class = c("tbl_df", "tbl", "data.frame")) > uuu # A tibble: 2 x 2 Id lists
uuu <- structure(list(Id = c("a", "b"),
lists = list(c(1:2), c(100:103))
),
.Names = c("Id", "lists"),
row.names = c(NA, 2L), class = c("tbl_df", "tbl", "data.frame"))
> uuu
# A tibble: 2 x 2
Id lists
* <chr> <list>
1 a <int [2]>
2 b <int [4]>
> unlist(res$res)
[1] 1.000000 1.414214 10.000000 10.049876 10.099505 10.148892
res <- uuu %>% mutate(res = map(lists, my_sqrt, id = id))
my_sqrt <- function(x, id) return(sqrt(x), id)
res
现在有一个新列,其中包含sqrt
函数的所有结果
现在我想在res
列中取消列出结果,但我还想有一个新列,指示结果来自哪个id
我可以这样取消列出结果:
uuu <- structure(list(Id = c("a", "b"),
lists = list(c(1:2), c(100:103))
),
.Names = c("Id", "lists"),
row.names = c(NA, 2L), class = c("tbl_df", "tbl", "data.frame"))
> uuu
# A tibble: 2 x 2
Id lists
* <chr> <list>
1 a <int [2]>
2 b <int [4]>
> unlist(res$res)
[1] 1.000000 1.414214 10.000000 10.049876 10.099505 10.148892
res <- uuu %>% mutate(res = map(lists, my_sqrt, id = id))
my_sqrt <- function(x, id) return(sqrt(x), id)
但我真正想要的是这样的东西(这里是手动完成的示例):
我们可以使用
unest
library(tidyverse)
res %>%
select(-lists) %>%
unnest