在函数NSE中按dplyr分组

在函数NSE中按dplyr分组,r,function,dplyr,R,Function,Dplyr,在管道函数调用中使用dplyr和groupby时遇到问题 可复制示例: outside_result<- ex_data %>% mutate(word2=reorder(word2,contribution)) %>% group_by(word1) %>% top_n(10,abs(contribution)) %>% group_by(word1,word2) %>% arrange(desc(contribution))

在管道函数调用中使用
dplyr
groupby
时遇到问题

可复制示例:

outside_result<- ex_data %>% 
  mutate(word2=reorder(word2,contribution)) %>% 
  group_by(word1) %>% 
  top_n(10,abs(contribution)) %>% 
  group_by(word1,word2) %>% 
  arrange(desc(contribution)) %>% 
  ungroup() %>% 
  mutate(word2 = factor(paste(word2,word1, sep = "__"),
                              levels=rev(paste(word2,word1,sep="__"))))
order_bars <- function(df,facetPanel,barCategory,value){
        df %>% mutate(barCategory=reorder(barCategory,value)) %>% 
          group_by(facetPanel) %>% 
          top_n(10,abs(value)) %>% 
          group_by(facetPanel,barCategory) %>% 
          arrange(desc(value)) %>% 
          ungroup() %>% 
          mutate(barCategory = factor(paste(barCategory,facetPanel, sep = "__"),
                                     levels=rev(paste(barCategory,facetPanel,sep="__"))))
      }
使用以下数据:

ex_data<- structure(list(word1 = c("no", "not", "not", "no", "not", "not", 
"not", "not", "no", "not", "no", "not", "not", "not", "no", "not", 
"no", "no", "not", "not", "not", "no", "not", "without", "never", 
"no", "not", "no", "no", "not", "not", "not", "no", "no", "no", 
"not", "not", "without", "never", "no", "not", "not", "not", 
"not", "not", "never", "no", "no", "not", "not"), word2 = c("doubt", 
"like", "help", "no", "want", "wish", "allow", "care", "harm", 
"sorry", "great", "leave", "pretend", "worth", "pleasure", "love", 
"danger", "want", "afraid", "doubt", "fail", "good", "forget", 
"feeling", "forget", "matter", "avoid", "chance", "hope", "forgotten", 
"miss", "perfectly", "bad", "better", "opportunity", "admit", 
"fair", "delay", "failed", "wish", "dislike", "distress", "refuse", 
"regret", "trust", "want", "evil", "greater", "better", "blame"
), score = c(-1L, 2L, 2L, -1L, 1L, 1L, 1L, 2L, -2L, -1L, 3L, 
-1L, -1L, 2L, 3L, 3L, -2L, 1L, -2L, -1L, -2L, 3L, -1L, 1L, -1L, 
1L, -1L, 2L, 2L, -1L, -2L, 3L, -3L, 2L, 2L, -1L, 2L, -1L, -2L, 
1L, -2L, -2L, -2L, -2L, 1L, 1L, -3L, 3L, 2L, -2L), n = c(102L, 
99L, 82L, 60L, 45L, 39L, 36L, 23L, 22L, 21L, 19L, 18L, 18L, 17L, 
16L, 16L, 15L, 15L, 15L, 14L, 14L, 13L, 13L, 13L, 12L, 12L, 12L, 
11L, 11L, 10L, 10L, 10L, 9L, 9L, 9L, 9L, 9L, 9L, 8L, 8L, 8L, 
8L, 8L, 8L, 8L, 7L, 7L, 7L, 7L, 7L), contribution = c(-102L, 
198L, 164L, -60L, 45L, 39L, 36L, 46L, -44L, -21L, 57L, -18L, 
-18L, 34L, 48L, 48L, -30L, 15L, -30L, -14L, -28L, 39L, -13L, 
13L, -12L, 12L, -12L, 22L, 22L, -10L, -20L, 30L, -27L, 18L, 18L, 
-9L, 18L, -9L, -16L, 8L, -16L, -16L, -16L, -16L, 8L, 7L, -21L, 
21L, 14L, -14L)), .Names = c("word1", "word2", "score", "n", 
"contribution"), row.names = c(NA, -50L), class = c("tbl_df", 
"tbl", "data.frame"))
R抛出以下错误:

Error: unknown variable to group by : facetPanel
Called from: resolve_vars(new_groups, tbl_vars(.data))

我怀疑需要调整
groupby
以获取命名变量,或者我必须使用
.dot
符号来引用列,虽然我只是想把它抛在脑后…

你需要学习如何使用1)SE版本的
dplyr
动词,如
groupby\uuu
mutate\uu
和2)神秘的
lazyeval::interp
。请仔细阅读
vignette(“nse”)

然后我们可以得出:

order_bars <- function(df, facetPanel, barCategory, value){
  require(lazyeval)
  df %>% 
    mutate_(barCategory = interp(~reorder(x, y), x = as.name(barCategory), 
                                 y = as.name(value))) %>% 
    group_by_(facetPanel) %>% 
    filter_(interp(~min_rank(desc(abs(x))) <= 10, x = as.name(value))) %>% 
    group_by_(facetPanel, barCategory) %>% 
    arrange_(interp(~desc(x), x = as.name(value))) %>% 
    ungroup() %>% 
    mutate_(barCategory = interp(
      ~factor(paste(x, y, sep = "__"), levels = rev(paste(x, y, sep = "__"))),
      x = as.name(barCategory), y = as.name(facetPanel)))
}

order_bars(ex_data, 'word1', 'word2', 'contribution')

理想情况下,您应该只完整地编写SE版本,并使用
lazyeval
将NSE版本链接到SE版本。我将把它作为一个练习留给读者。

对于
rlang_0.4.0
dplyr_0.8.2
,我们可以使用整洁的求值操作符({…})或curly-curly,它将引号和unquote抽象为一个插值步骤

library(rlang)
library(dplyr)
order_barsN <- function(df, facetPanel, barCategory, value) {
    df %>% 
        mutate(barCategory = reorder({{barCategory}}, {{value}}))%>%
        group_by({{facetPanel}}) %>%
        filter(min_rank(desc(abs({{value}}))) <= 10) %>%
        group_by({{facetPanel}}, {{barCategory}}) %>%
        arrange(desc({{value}})) %>%
        ungroup %>%
        mutate(barCategory = factor(str_c({{barCategory}}, {{facetPanel}}, sep="__"),
                levels = rev(str_c({{barCategory}}, {{facetPanel}}, sep="__"))))

        }


out2 <- order_barsN(ex_data, word1, word2, contribution)
库(rlang)
图书馆(dplyr)
订单数量%
mutate(barCategory=重新排序({{barCategory},{{value}}))%>%
分组依据({facetPanel}})%>%
过滤器(最小秩(desc(abs({{value})))%
分组依据({facetPanel},{{barCategory}})%>%
排列(desc({value}}))%>%
解组%>%
mutate(barCategory=factor(str_c({{barCategory}},{{facetPanel}},sep=“{uu”),
levels=rev(str_c({{barCategory},{{{facetPanel}},sep=“u”))
}

out2这是我第一次遇到SE,这是一个很好的学习机会…谢谢你的指导!awwww很好的回答axeman但是伙计,SE评估的东西是horrible@Noobie是的,在我看来,一个人用丑陋来为NSE的美丽买单在使用tidyverse时使用SE。此行为已被更改。“dplyr现在使用tidy求值语义。NSE谓词仍然捕获其参数,但您现在可以取消这些参数的部分引用。这提供了NSE谓词的完全可编程性。因此,带下划线的版本现在是多余的。”请参阅
# A tibble: 25 × 6
   word1    word2 score     n contribution  barCategory
   <chr>    <chr> <int> <int>        <int>       <fctr>
1    not     like     2    99          198    like__not
2    not     help     2    82          164    help__not
3     no    great     3    19           57    great__no
4     no pleasure     3    16           48 pleasure__no
5    not     love     3    16           48    love__not
6    not     care     2    23           46    care__not
7    not     want     1    45           45    want__not
8    not     wish     1    39           39    wish__not
9     no     good     3    13           39     good__no
10   not    allow     1    36           36   allow__not
order_bars <- function(df,facetPanel,barCategory,value){
  facetPanel <- substitute(facetPanel)
  barCategory <- substitute(barCategory)
  value <- substitute(value)

  require(lazyeval)
  df %>% 
    mutate_(barCategory = interp(~reorder(x, y), x = barCategory, y = value)) %>% 
    group_by_(facetPanel) %>% 
    filter_(interp(~min_rank(desc(abs(x))) <= 10, x = value)) %>% 
    group_by_(facetPanel, barCategory) %>% 
    arrange_(interp(~desc(x), x = value)) %>% 
    ungroup() %>% 
    mutate_(barCategory = interp(
      ~factor(paste(x, y, sep = "__"), levels = rev(paste(x, y, sep = "__"))),
      x = barCategory, y = facetPanel))
}

order_bars(ex_data, word1, word2, contribution)
library(rlang)
library(dplyr)
order_barsN <- function(df, facetPanel, barCategory, value) {
    df %>% 
        mutate(barCategory = reorder({{barCategory}}, {{value}}))%>%
        group_by({{facetPanel}}) %>%
        filter(min_rank(desc(abs({{value}}))) <= 10) %>%
        group_by({{facetPanel}}, {{barCategory}}) %>%
        arrange(desc({{value}})) %>%
        ungroup %>%
        mutate(barCategory = factor(str_c({{barCategory}}, {{facetPanel}}, sep="__"),
                levels = rev(str_c({{barCategory}}, {{facetPanel}}, sep="__"))))

        }


out2 <- order_barsN(ex_data, word1, word2, contribution)
out1 <- order_bars(ex_data, word1, word2, contribution)
identical(out1, out2)
#[1] TRUE