R 删除基于杠杆值的观察值

R 删除基于杠杆值的观察值,r,linear-regression,R,Linear Regression,在检查了我的数据之后,我的lm()模型中似乎有一些比预期(或希望)更大的杠杆值。我希望根据观察结果超过杠杆阈值来删除它们 df <- df[ df$title_year >= 2000 , ] model <- lm( df$gross ~ . , data= df ) lev <- hatvalues( model3 ) lev_val <- lev[ lev > 2 * 8/2546 > names(lev_val) [1] "282"

在检查了我的数据之后,我的
lm()
模型中似乎有一些比预期(或希望)更大的杠杆值。我希望根据观察结果超过杠杆阈值来删除它们

df <- df[ df$title_year >= 2000 , ] 
model <- lm( df$gross ~ . , data= df ) 

lev <- hatvalues( model3 ) 
lev_val <- lev[ lev > 2 * 8/2546

> names(lev_val)
  [1] "282"  "90"   "103"  "25"   "189"  "53"   "147"  "51"   "1526" "1"    "133"  "34"   "273"  "1852" "2172" "5"    "916"  "200"  "79"   "50"  
 [21] "29"   "632"  "266"  "149"  "28"   "26"   "107"  "105"  "202"  "144"  "203"  "8"    "414"  "54"   "279"  "394"  "4"    "155"  "10"   "1539"
 [41] "27"   "1318" "153"  "109"  "1790" "1327" "918"  "1275" "1055" "85"   "11"   "1543" "919"  "33"   "481"  "759"  "43"   "2404" "30"   "920" 
 [61] "212"  "123"  "42"   "223"  "58"   "118"  "111"  "32"   "281"  "88"   "1075" "1061" "421"  "1517" "487"  "2084" "774"  "934"  "1069" "86"  
 [81] "113"  "221"  "37"   "60"   "112"  "304"  "1347" "117"  "697"  "102"  "1472" "225"  "773"  "2"    "219"  "121"  "151"  "1856" "18"   "122" 
[101] "182"  "518"  "1084" "2014" "776"  "300"  "71"   "125"  "2070" "1854" "97"   "1288" "38"   "1087" "2004" "227"  "1747" "64"   "98"   "264" 
[121] "23"   "1729" "150"  "65"   "1559" "36"   "52"   "13"   "128"  "328"  "39"   "524"  "886"  "613"  "2195" "2441" "2446" "2096" "84"   "1522"
[141] "15"   "1800" "462"  "41"   "1100" "1804" "14"   "162"  "1336" "232"  "2193" "24"   "529"  "2088" "787"  "68"   "433"  "785"  "66"   "1340"
[161] "1863" "1587" "788"  "950"  "2450" "1717" "158"  "682"  "2531" "951"  "1110" "535"  "539"  "1478" "35"   "72"   "2136" "547"  "1887" "21"  
[181] "2208" "1873" "1126" "2144" "1805" "2211" "1722" "1874" "1721" "91"   "16"   "2451" "410"  "31"   "1153" "1593" "280"  "1878" "366"  "20"  
[201] "2407" "69"   "1605" "1606" "694"  "1881" "403"  "73"   "303"  "1149" "955"  "1144" "893"  "1138" "2221" "140"  "404"  "819"  "1365" "2225"
[221] "1374" "1690" "1485" "442"  "1150" "1614" "1486" "78"   "1894" "1998" "185"  "2236" "2229" "1373" "1155" "1369" "1817" "184"  "1305" "9"   
[241] "2017" "331"  "1910" "466"  "1621" "566"  "1619" "1372" "2239" "570"  "1908" "947"  "1906" "587"  "170"  "1629" "17"   "308"  "2112" "2257"
[261] "400"  "575"  "1166" "402"  "1745" "1733" "1818" "372"  "962"  "329"  "829"  "966"  "67"   "1174" "2248" "703"  "1622" "1624" "1623" "574" 
[281] "2255" "269"  "1013" "1180" "1387" "1627" "40"   "1924" "2270" "2260" "1631" "95"   "1628" "1184" "2423" "2050" "1481" "1388" "1037" "2060"
[301] "843"  "1746" "1202" "975"  "977"  "1392" "256"  "2109" "2541" "333"  "1495" "1047" "2426" "2478" "2277" "250"  "2282" "981"  "92"   "848" 
[321] "2290" "75"   "1995" "1646" "2143" "688"  "2123" "2488" "2499" "255"  "1941" "1190" "914"  "1189" "2487" "1911" "1768" "382"  "2305" "1512"
[341] "2113" "2127" "2329" "980"  "1203" "1204" "582"  "1949" "2185" "600"  "588"  "1422" "1468" "1963" "2425" "2331" "2494" "2122" "1273" "2415"
[361] "2147" "2335" "2500" "2276" "864"  "2397" "2504" "1235" "1269" "2361" "2360" "2119" "1009" "2371" "2362" "709"  "1976" "1216" "2039" "594" 
[381] "595"  "2517" "77"   "2124" "2373" "1680" "1682" "998"  "259"  "1984" "2386" "1785" "1683" "143"  "1990" "1179" "2163" "2418" "82"
df=2000,]

模型纯粹作为一个编程问题,您需要
df[!which(rownames(df)%in%remove),]
,因为没有
%nin%
。另外请注意,您需要的是
行.名称
而不是
名称
,因为您要选择行而不是列。或者,为什么不简单地使用<代码> DF[LV?这可能是非常糟糕的统计数据。你应该考虑对你的代码> Y < /C>进行转换。没有更多的细节,就不可能进行故障处理。你要的答案是<代码> DF2= DF[(LeV>2×8/2546),] /<代码>,这可能不是你真正想要的答案。