使用R中的滑块绘制多个数据帧的热图
我有多个data.frames,每一个都代表不同时间点的个体成对交互 下面是我的data.frames的外观示例使用R中的滑块绘制多个数据帧的热图,r,ggplot2,plotly,heatmap,ggplotly,R,Ggplot2,Plotly,Heatmap,Ggplotly,我有多个data.frames,每一个都代表不同时间点的个体成对交互 下面是我的data.frames的外观示例 df1 <- matrix(data = rexp(9, rate = 10), nrow = 3, ncol = 3) df2 <- matrix(data = rexp(16, rate = 10), nrow = 4, ncol = 4) df3 <- matrix(data = rexp(4, rate = 10), nrow = 2, ncol = 2)
df1 <- matrix(data = rexp(9, rate = 10), nrow = 3, ncol = 3)
df2 <- matrix(data = rexp(16, rate = 10), nrow = 4, ncol = 4)
df3 <- matrix(data = rexp(4, rate = 10), nrow = 2, ncol = 2)
df1遵循正弦波滑块
示例可以这样实现。我的方法的第一步涉及将矩阵转换为具有x、y、z列的数据帧。其次,我们绘制热图而不是线
df1 <- matrix(data = rexp(9, rate = 10), nrow = 3, ncol = 3)
df2 <- matrix(data = rexp(16, rate = 10), nrow = 4, ncol = 4)
df3 <- matrix(data = rexp(4, rate = 10), nrow = 2, ncol = 2)
library(tibble)
library(tidyr)
library(plotly)
# Make dataframes
d <- lapply(list(df1, df2, df3), function(d) {
d %>%
as_tibble(.colnames = seq(ncol(.))) %>%
rowid_to_column("x") %>%
pivot_longer(-x, names_to = "y", values_to = "z") %>%
mutate(y = stringr::str_extract(y, "\\d"),
y = as.numeric(y))
})
aval <- list()
for(step in seq_along(d)){
aval[[step]] <-list(visible = FALSE,
name = paste0('v = ', step),
x = d[[step]]$x,
y = d[[step]]$y,
z = d[[step]]$z)
}
aval[1][[1]]$visible = TRUE
steps <- list()
fig <- plot_ly()
for (i in seq_along(aval)) {
fig <- add_trace(fig, x = aval[i][[1]]$x, y = aval[i][[1]]$y, z = aval[i][[1]]$z, visible = aval[i][[1]]$visible,
name = aval[i][[1]]$name, type = "heatmap")
fig
step <- list(args = list('visible', rep(FALSE, length(aval))), method = 'restyle')
step$args[[2]][i] = TRUE
steps[[i]] = step
}
fig <- fig %>%
layout(sliders = list(list(active = 0,
currentvalue = list(prefix = "Heatmap: "),
steps = steps)))
fig
df1%
突变(y=stringr::str_extract(y,“\\d”),
y=作为数字(y))
})
阿瓦尔