如何在RabbitMQ中使用不同的路由密钥将多个消息发布到单个队列?
这是我的密码:如何在RabbitMQ中使用不同的路由密钥将多个消息发布到单个队列?,rabbitmq,Rabbitmq,这是我的密码: package pushnotiruntest; import com.rabbitmq.client.BuiltinExchangeType; import com.rabbitmq.client.Channel; import com.rabbitmq.client.Connection; import com.rabbitmq.client.ConnectionFactory; import java.io.IOException; import java.util.co
package pushnotiruntest;
import com.rabbitmq.client.BuiltinExchangeType;
import com.rabbitmq.client.Channel;
import com.rabbitmq.client.Connection;
import com.rabbitmq.client.ConnectionFactory;
import java.io.IOException;
import java.util.concurrent.TimeoutException;
import java.util.logging.Level;
import java.util.logging.Logger;
public class Send extends Thread {
String name = "";
String app_type = "";
private static final String EXCHANGE_NAME = "topic_exchange";
public void run()
{
ConnectionFactory connFac = new ConnectionFactory();
connFac.setHost("localhost");
try {
Connection conn = connFac.newConnection();
Channel channel = conn.createChannel();
channel.exchangeDeclare(EXCHANGE_NAME, BuiltinExchangeType.TOPIC);
for(int j=1; j<=20000; j++)
{
//randomWait();
String routingKey = j+"."+"update"+"."+app_type;
String msg = name;
channel.basicPublish(EXCHANGE_NAME, routingKey, null, msg.getBytes("UTF-8"));
System.out.println("Sent " + routingKey + " : " + msg + "");
}
channel.close();
conn.close();
} catch (IOException ex) {
Logger.getLogger(Send.class.getName()).log(Level.SEVERE, null, ex);
System.out.println("Exception1 :--"+ex);
} catch (TimeoutException ex) {
Logger.getLogger(Send.class.getName()).log(Level.SEVERE, null, ex);
System.out.println("Exception 2:--"+ex);
}
}
/*void randomWait()
{
try {
Thread.currentThread().sleep((long)(3*Math.random()));
} catch (InterruptedException x) {
System.out.println("Interrupted!");
}
}*/
public static void main(String[] args) {
// TODO code application logic here
Send test1 = new Send();
test1.name = "Hello ANDROID";
test1.app_type = "ANDROID";
Send test2 = new Send();
test2.name = "Hello IOS";
test2.app_type = "IOS";
Send test3 = new Send();
test3.name = "Hello WINDOWS";
test3.app_type = "WINDOWS";
test1.start();
test2.start();
test3.start();
}
}
//javac -cp amqp-client-4.0.2.jar Send.java Recv.java
//java -cp .;amqp-client-4.0.2.jar;slf4j-api-1.7.21.jar;slf4j-simple-1.7.22.jar Recv
//java -cp .;amqp-client-4.0.2.jar;slf4j-api-1.7.21.jar;slf4j-simple-1.7.22.jar
Send
package-pushnotiruntest;
导入com.rabbitmq.client.BuiltinExchangeType;
导入com.rabbitmq.client.Channel;
导入com.rabbitmq.client.Connection;
导入com.rabbitmq.client.ConnectionFactory;
导入java.io.IOException;
导入java.util.concurrent.TimeoutException;
导入java.util.logging.Level;
导入java.util.logging.Logger;
公共类发送扩展线程{
字符串名称=”;
字符串app_type=“”;
私有静态最终字符串交换\u NAME=“主题交换”;
公开募捐
{
ConnectionFactory connFac=新的ConnectionFactory();
connFac.setHost(“localhost”);
试一试{
连接conn=connFac.newConnection();
Channel=conn.createChannel();
channel.ExchangeClare(EXCHANGE\u名称,BuiltinExchangeType.TOPIC);
对于(int j=1;j如果需要两个消费者,则必须使用两个队列。
如果从交换
到队列
您无法在订阅期间决定路由密钥,则绑定将被禁用
您可以将更多路由密钥绑定到同一队列,但不能使用该密钥进行过滤
我想你需要这样的东西:
channel.exchangeDeclare(EXCHANGE_NAME, BuiltinExchangeType.TOPIC);
channel.queueDeclare(QUEUE_NAME_1, true, false, false, null);
channel.queueDeclare(QUEUE_NAME_2, true, false, false, null);
channel.queueBind(QUEUE_NAME_1, EXCHANGE_NAME, "my.rk.1");
channel.queueBind(QUEUE_NAME_2, EXCHANGE_NAME, "my.rk.2");
channel_consumer_1.basicConsume(QUEUE_NAME_1, false, new DefaultConsumer(channel_consumer) {...}
....
channel_consumer_2.basicConsume(QUEUE_NAME_2, false, new DefaultConsumer(channel_consumer) {...}
如果我必须向不同的应用程序发送数千条消息(如推送通知),那么为每个应用程序创建队列可能会创建大量队列,这可能很难由服务器处理。我想要的是根据优先级将消息发布到队列中,并将消息返回给各自的消费者(即根据应用程序id)。您必须为设备创建一个队列。您可以解释一下,您知道如何使用不同的绑定密钥将多个消费者绑定到单个队列吗?正如我所说:您可以使用不同的路由密钥绑定队列,而不是绑定消费者