Reactjs 在React导航中返回主屏幕时如何调用构造函数?
我有一个Reactjs 在React导航中返回主屏幕时如何调用构造函数?,reactjs,react-native,react-native-android,react-navigation,react-native-ios,Reactjs,React Native,React Native Android,React Navigation,React Native Ios,我有一个createBottomTabNavigator,其中有一个createStackNavigator: const SettingsStack = createStackNavigator({ SettingsScreen: { screen: SettingsClass, //1st screen }, EditProfile: { screen: EditProfileClass . //2nd screen }, }, 当我从EditProfil
createBottomTabNavigator
,其中有一个createStackNavigator
:
const SettingsStack = createStackNavigator({
SettingsScreen: {
screen: SettingsClass, //1st screen
},
EditProfile: {
screen: EditProfileClass . //2nd screen
},
},
当我从EditProfile屏幕移回主SettingsScreen时,我希望再次运行SettingsScreen中的componentWillMount()(每次返回时)。现在它只运行一次。或者在SettingsScreen中创建一个函数,该函数在我从EditProfile屏幕返回到主SettingsScreen时运行。这样,我的主设置屏幕现在将刷新最新的配置文件信息。如何实现这一点?您可以在
SettingsScreen
class SettingsScreen extends Component {
componentDidMount() {
this.focusListener = this.props.navigation.addListener('didFocus', () => {
// Call your refresh code here
});
}
componentWillUnmount() {
this.focusListener.remove();
}
}