Reactjs 如何使用useReducer在对象状态中设置多个值？

我试图使用函数的结果在reducer中设置对象状态中的两个值。正在为

结果

获取未定义的值

const initialState = {
    charCountsFirstName: [7, 4, 2, 2, 2, 2, 2, 4, 5, 5, 5, 9],
    allFreqsFirst: {
        labels: [],
        data: [],
    },
}

const getAllFrequencies = (arr) => {
    function getFreqs(arr) {
        // DOO A BUNCH OF STUFF...
        return [a, b];
    }
    const result = getFreqs(arr);
};

const reducer = (state, action) => {
    switch (action.type) {
        case 'SET_ALL_FREQS_FIRSTNAME':
            let result = getAllFrequencies(charCountsFirstName);

            return { 
                ...state, 
                allFreqsFirst: {
                    labels: result[0],
                    data: result[1],
                } 
            };

        default:
            return state;
    }
}

const StateProvider = ({ children }) => {
    const [newState, dispatch] = useReducer(reducer, initialState);

    // CALL DISPATCH AFTER GETTING DATA FROM API CALL
    dispatch({ type: 'SET_MOST_FREQUENT_FIRSTNAME' });
}

---

确保使用

state.charCountsFirstName

而不仅仅是

charCountsFirstName

。。。
开关（动作类型）{
案例“设置所有频率首名”：
让结果=getAllFrequencies（state.charCountsFirstName）；
const getAllFrequencies = (arr) => {
    function getFreqs(arr) {
        // DOO A BUNCH OF STUFF...
        return [a, b];
    }
    const result = getFreqs(arr);
    // Maybe you need to return the val ==> 'result';
    // Like: return result;
};