Reactjs 如何从父对象打开对话框材质ui
我有一个父组件,它有一个抽屉和一些图标按钮,我希望当我首先单击图标按钮时,子组件加载对话框,然后如果接受对话框关闭,子组件加载的其余部分Reactjs 如何从父对象打开对话框材质ui,reactjs,react-hooks,Reactjs,React Hooks,我有一个父组件,它有一个抽屉和一些图标按钮,我希望当我首先单击图标按钮时,子组件加载对话框,然后如果接受对话框关闭,子组件加载的其余部分 父组件 <Child sendId = {id} OpenDialog={true}/> const handleClose = () => { OpenDialog = false }; return OpenDialog ? <Dialog open={OpenDialog} onClose={
父组件
<Child sendId = {id} OpenDialog={true}/>
const handleClose = () => {
OpenDialog = false
};
return
OpenDialog ?
<Dialog open={OpenDialog} onClose={handleClose} >
some Content
</Dialog>
: <div>
rest of child componet
</div>
const [openDialog, setOpenDialog] = useState(false);
<Child sendId = {id} openDialog={openDialog} setOpenDialog={setOpenDialog} />
子组件
<Child sendId = {id} OpenDialog={true}/>
const handleClose = () => {
OpenDialog = false
};
return
OpenDialog ?
<Dialog open={OpenDialog} onClose={handleClose} >
some Content
</Dialog>
: <div>
rest of child componet
</div>
const [openDialog, setOpenDialog] = useState(false);
<Child sendId = {id} openDialog={openDialog} setOpenDialog={setOpenDialog} />
consthandleclose=()=>{
OpenDialog=false
};
返回
OpenDialog?
一些内容
:
孩子的其余部分
但是它总是打开的,我想如果我关闭doalog并单击父组件,你必须控制父组件中对话框的状态 家长
<Child sendId = {id} OpenDialog={true}/>
const handleClose = () => {
OpenDialog = false
};
return
OpenDialog ?
<Dialog open={OpenDialog} onClose={handleClose} >
some Content
</Dialog>
: <div>
rest of child componet
</div>
const [openDialog, setOpenDialog] = useState(false);
<Child sendId = {id} openDialog={openDialog} setOpenDialog={setOpenDialog} />
const[openDialog,setOpenDialog]=useState(false);
儿童
const handleClose = () => {
setOpenDialog(false)
};
return
OpenDialog ?
<Dialog open={openDialog} onClose={handleClose} >
some Content
</Dialog>
: <div>
rest of child componet
</div>
consthandleclose=()=>{
setOpenDialog(错误)
};
返回
OpenDialog?
一些内容
:
孩子的其余部分