Regex 如何在awk中解析和替换GPU日志？

我有grep输出：

Nov 07 16:03:23 SA1789 miner[1397]: GPU4 not responding                   
Nov 07 16:03:23 SA1789 miner[1397]: Thread(s) not responding. Restarting.
Nov 07 16:02:25 SA0888 miner[1505]: GPU12 not responding                            
Nov 07 16:02:25 SA0888 miner[1505]: Thread(s) not responding. Restarting.           
Nov 07 16:04:17 SA0888 miner[1505]: GPU12 not responding                       
Nov 07 16:04:17 SA0888 miner[1505]: Thread(s) not responding. Restarting.

想要得到这个：

Nov 07 16:03:23 ==> GPU4
Nov 07 16:02:25 ==> GPU12
Nov 07 16:04:17 ==> GPU12

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对不起，我不在awk，只需要专家提供快速解决方案。

简单

awk

表达式：

$ awk '/GPU/{ print $1, $2, $3, "==>", $6 }' file
Nov 07 16:03:23 ==> GPU4
Nov 07 16:02:25 ==> GPU12
Nov 07 16:04:17 ==> GPU12

$ awk '/GPU/{ print $1, $2, $3, "==>", $6 }' file
Nov 07 16:03:23 ==> GPU4
Nov 07 16:02:25 ==> GPU12
Nov 07 16:04:17 ==> GPU12