在REGEXP_SUBSTR中使用connect by，而不中断多行的结果

上面的脚本只有@yahoo.com前面的正则表达式

SELECT CHR(91)||'a-zA-Z0-9._%-'||CHR(93)||'+'|| listagg(REGEXP_SUBSTR('aaa@yahoo.com, bbb@hotmail.com', '@'||CHR(91)||'^,'||CHR(93)||'+', 1, LEVEL), ', ') within group (order by level) as domain
FROM DUAL
CONNECT BY REGEXP_SUBSTR('aaa@yahoo.com, bbb@hotmail.com','@'||CHR(91)||'^,'||CHR(93)||'+', 1, LEVEL) IS NOT NULL
order by 1;

预期结果：

 [a-zA-Z0-9._%-]+@yahoo.com, @hotmail.com

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当然；把它们聚合回来

[a-zA-Z0-9._%-]+@yahoo.com, [a-zA-Z0-9._%-]+@hotmail.com

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如果要将regexp前缀放在所有域中，则

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谢谢，它起作用了。如果我需要两个域都加上前缀reg exp。。目前只有第一个条目有。[a-zA-Z0-9.\u%-]+@yahoo.com，@hotmail.com，恐怕我不明白这个问题。请编辑您的初始帖子并添加示例数据以及所需的输出。完成，抱歉造成混淆。我编辑了答案并添加了更多代码。看一看。所有商品，非常感谢；）

SQL> SELECT listagg(REGEXP_SUBSTR('aaa@yahoo.com, bbb@hotmail.com', '@'||CHR(91)||'^,'||CHR(93)||'+', 1, LEVEL), ', ') within group (order by level) as domain
  2  FROM DUAL
  3  CONNECT BY REGEXP_SUBSTR('aaa@yahoo.com, bbb@hotmail.com','@'||CHR(91)||'^,'||CHR(93)||'+', 1, LEVEL) IS NOT NULL
  4  order by 1;

DOMAIN
----------------------------------------------------------------------------------------------------
@yahoo.com, @hotmail.com

SQL>

SQL>     SELECT LISTAGG (   '[a-zA-Z0-9._%-]+'
  2                      || REGEXP_SUBSTR ('aaa@yahoo.com, bbb@hotmail.com',
  3                                        '@' || CHR (91) || '^,' || CHR (93) || '+',
  4                                        1,
  5                                        LEVEL),
  6                      ', ')
  7             WITHIN GROUP (ORDER BY LEVEL) AS domain
  8        FROM DUAL
  9  CONNECT BY REGEXP_SUBSTR ('aaa@yahoo.com, bbb@hotmail.com',
 10                            '@' || CHR (91) || '^,' || CHR (93) || '+',
 11                            1,
 12                            LEVEL)
 13                IS NOT NULL;

DOMAIN
-----------------------------------------------------------------------------------------------
[a-zA-Z0-9._%-]+@yahoo.com, [a-zA-Z0-9._%-]+@hotmail.com

SQL>