Regex grep中的多重表达

我想找到那一行

以“partition”（该单词前面的空格是ok）开头

后面的行将只包含“'）”（允许空白）

我设法做到了这一点：

grep -B1 ')' file.log | grep 'partition'

我相信我缺少的是如何在第一个grep命令中添加另一个表达式。这样我就可以加上“不等于”（“）

file.log

 parameters ('storage "IDXD_ITEM_LOAN_S0007"'),
 partition "P_ITEM_LOAN_0000000221"
 parameters ('storage "IDXD_ITEM_LOAN_S0008"'),
 partition "P_ITEM_LOAN_0000000231"
 parameters ('storage "IDXD_ITEM_LOAN_S0009"'),
   partition "P_ITEM_LOAN_0000001831"
 parameters ('storage "IDXD_ITEM_LOAN_S0010"')
 )
/

 parameters ('storage "IDXD_ITEM_LOAN_S0007"'),
 partition "P_ITEM_LOAN_0000000221"
 parameters ('storage "IDXD_ITEM_LOAN_S0008"'),
 partition "P_ITEM_LOAN_0000000231"
 parameters ('storage "IDXD_ITEM_LOAN_S0009"'),
 partition "P_ITEM_LOAN_0000001832"
 )
/


 parameters ('storage "IDXD_ITEM_LOAN_S0007"'),
 partition "P_ITEM_LOAN_0000000221"
 parameters ('storage "IDXD_ITEM_LOAN_S0008"'),
 partition "P_ITEM_LOAN_0000000231"
 parameters ('storage "IDXD_ITEM_LOAN_S0009"'),
  partition "P_ITEM_LOAN_0000001833"
)
/

 parameters ('storage "IDXD_ITEM_LOAN_S0007"'),
 partition "P_ITEM_LOAN_0000000221"
 parameters ('storage "IDXD_ITEM_LOAN_S0008"'),
 partition "P_ITEM_LOAN_0000000231"
  parameters ('storage "IDXD_ITEM_LOAN_S0009"'),
   partition "P_ITEM_LOAN_0000001834"
     )
/

期望输出

partition "P_ITEM_LOAN_0000001832"
partition "P_ITEM_LOAN_0000001833"
partition "P_ITEM_LOAN_0000001834"

如果你想去掉前导空格，你可以通过sed管道你可以使用

grep-p（PCRE）

：

---

我不按顺序问。这就是为什么我相信只有grep才能完成。我尝试了

-v

，得到了奇怪的结果。无论如何，从您的示例文件中，您只需使用

cat file.txt | grep“分区”就可以得到所需的内容

Ahn抱歉，现在我明白了！不，它返回所有

分区

行通过搜索其他内容来解决它。现在我搜索

/

而不是

）

，在grep中我使用

-B2

类似的内容

cat file.txt | grep-B2”/“| grep”分区“

Nice！干得好，有用。谢谢

grep -PB1 '\s\)|^\)' tst.txt | grep 'partition'

grep -P '^ *partition(?=.*?\n *\) *\n)' file.log 
 partition "P_ITEM_LOAN_0000001832"
  partition "P_ITEM_LOAN_0000001833"
   partition "P_ITEM_LOAN_0000001834"