Regex 正则表达式中的字符串替换
我试图用正则表达式替换字符串中的文本。我用c#完成了它,使用了相同的模式,但在swift中,它没有按照需要工作 这是我的密码:Regex 正则表达式中的字符串替换,regex,swift2,xcode7,Regex,Swift2,Xcode7,我试图用正则表达式替换字符串中的文本。我用c#完成了它,使用了相同的模式,但在swift中,它没有按照需要工作 这是我的密码: var pattern = "\\d(\\()*[x]" let oldString = "2x + 3 + x2 +2(x)" let newString = oldString.stringByReplacingOccurrencesOfString(pattern, withString:"*" as String, options:NSStringCompa
var pattern = "\\d(\\()*[x]"
let oldString = "2x + 3 + x2 +2(x)"
let newString = oldString.stringByReplacingOccurrencesOfString(pattern, withString:"*" as String, options:NSStringCompareOptions.RegularExpressionSearch, range:nil)
print(newString)
更换后我想要的是:
“2*x+3+x2+2*(x)”
我得到的是:
“*+3+x2+*)”
试试这个:
(?
Try this:
(?<=\d)(?=x)|(?<=\d)(?=\()
This pattern matches not any characters in the given string, but zero width positions in between characters.
For example, (?<=\d)(?=x) This matches a position in between a digit and 'x'
(?<= is look behind assertion (?= is look ahead.
(?<=\d)(?=\() This matches the position between a digit and '('
So the pattern before escaping:
(?<=\d)(?=x)|(?<=\d)(?=\()
Pattern, after escaping the parentheses and '\'
\(?<=\\d\)\(?=x\)|\(?<=\\d\)\(?=\\\(\)