Regex 使用正则表达式捕获不正确的文本模式格式

我有空文件夹，它们的开头有

NA-

。这些文件的正确格式应为

“NA-文件夹名称”

不幸的是，并非所有人都遵循这种命名惯例。我试图编写一个正则表达式来捕获NA的所有模式，即格式错误或重复NA-

到目前为止我想出的正则表达式是

N？A-（（？！[0-9.A-MO-Z][B-Z]|）N？A-）

下面是我用来测试它的文件夹名。名称中不正确的具有NA-格式不正确，我想在以下位置捕获NA-格式：

NA -IncorrectFolderName1
N A-1. IncorrectFolderName2
N A- 1. IncorrectFolderName3
NA-IncorrectFolderName4
N A -1.IncorrectFolderName5
NA -NA -IncorrectFolderName6
NA - NA -IncorrectFolderName7
N A - N A - IncorrectFolderName8
N A - NA - IncorrectFolderName9

NA - CorrectFolderName1
NA - 1CorrectFolderName2
NA - 1. CorrectFolderName3

请参阅此处的代码，以了解我正在尝试执行的操作：

我的代码无法捕获的唯一错误格式是：

N A- 1. IncorrectFolderName3

正则表达式不应捕获格式正确的“NA-”文件夹，如下所示。这些代码不应被捕获

RegularFolderName1
NA - CorrectFolderName1
NA - 1CorrectFolderName2
NA - 1. CorrectFolderName3

我一直在研究正则表达式，我很接近，但我似乎不知道如何编写它来找到错误代码的所有所需模式。任何帮助都将不胜感激。

我想，也许吧

(?:(?:N\s*A\s*)-\s*){2}|N\s+A\s*-\s*(?=\d+\.\s*)|NA-|NA\s+-(?=\S)

或者，一些类似的表达式可以交替使用，这样编写和调试就简单多了

我不确定我们会在结尾处捕获什么，也不想在结尾处捕获什么，任何您不想滑动/捕获的结尾部分，您只需将其置于正向前瞻

（？=）

，这是一种零宽度断言，例如：

NA\s+-(?=\S)

正则表达式电路 可视化正则表达式：

---

如果您希望简化/修改/探索表达式，将在的右上面板中进行解释。如果您愿意，还可以在中查看它与一些示例输入的匹配情况

---

---

使用您的示例，这是有效的：

$foldernames =  'NA -IncorrectFolderName1',
                'N A-1. IncorrectFolderName2',
                'N A- 1. IncorrectFolderName3',
                'NA-IncorrectFolderName4',
                'N A -1.IncorrectFolderName5',
                'NA -NA -IncorrectFolderName6',
                'NA - NA -IncorrectFolderName7',
                'N A - N A - IncorrectFolderName8',
                'N A - NA - IncorrectFolderName9',
                'RegularFolderName1',
                'NA - CorrectFolderName1',
                'NA - 1CorrectFolderName2',
                'NA - 1. CorrectFolderName3'

$newNames = $foldernames | ForEach-Object { $_ -replace '^(?:(N\s*A\s*-\s*))+(.+)', 'NA - $2' }

$newNames

结果:

正则表达式详细信息：

(?:              Match the regular expression below
   (             Match the regular expression below and capture its match into backreference number 1
      N          Match the character “N” literally
      \s         Match a single character that is a “whitespace character” (spaces, tabs, line breaks, etc.)
         *       Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
      A          Match the character “A” literally
      \s         Match a single character that is a “whitespace character” (spaces, tabs, line breaks, etc.)
         *       Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
      -          Match the character “-” literally
      \s         Match a single character that is a “whitespace character” (spaces, tabs, line breaks, etc.)
         *       Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
   )
)+               Between one and unlimited times, as many times as possible, giving back as needed (greedy)
(                Match the regular expression below and capture its match into backreference number 2
   .             Match any single character that is not a line break character
      +          Between one and unlimited times, as many times as possible, giving back as needed (greedy)
)

---

请尝试替换“^（？：N\s*A\b\P{L}*）+”，请参阅或，

^N\s*A（？:\s*（？：-\s*）？N\s*A）*（？：\s*-\s*（？：\d+\）*\s*，

，请参阅。如果你能精确描述需求的其他部分，这将很有帮助。你打算用你想要的模式重命名这些项目吗？如果是这样，那么您可能只需要获取所有以

N

开头、后跟一个或多个

A

或``的文件，然后是连字符。一旦你有了这个列表，在连字符上拆分，取最后一个项目，并添加正确的前缀。

-不匹配“^NA-（？！NA-”

-谢谢你的帮助。我在这件事上伤了脑筋。也感谢您提供的额外见解。对此感到抱歉，只是注意到它仍然可以捕获那些在模式后面有数字的数字。那些像

na-1。错误的文件夹名称2，不适用-1。不正确的文件夹名称3，不适用-1。不正确的文件夹名称5

。不管怎么说？再次谢谢你。按预期工作。关于Lookaround断言，我有很多东西需要学习。

(?:              Match the regular expression below
   (             Match the regular expression below and capture its match into backreference number 1
      N          Match the character “N” literally
      \s         Match a single character that is a “whitespace character” (spaces, tabs, line breaks, etc.)
         *       Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
      A          Match the character “A” literally
      \s         Match a single character that is a “whitespace character” (spaces, tabs, line breaks, etc.)
         *       Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
      -          Match the character “-” literally
      \s         Match a single character that is a “whitespace character” (spaces, tabs, line breaks, etc.)
         *       Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
   )
)+               Between one and unlimited times, as many times as possible, giving back as needed (greedy)
(                Match the regular expression below and capture its match into backreference number 2
   .             Match any single character that is not a line break character
      +          Between one and unlimited times, as many times as possible, giving back as needed (greedy)
)