Reporting services 如何使用Reporting Services表达式从上一个值中减去行的值?
使用以下SQL查询:Reporting services 如何使用Reporting Services表达式从上一个值中减去行的值?,reporting-services,reportingservices-2005,Reporting Services,Reportingservices 2005,使用以下SQL查询: SELECT TOP (100) PERCENT ID_BADGE, LEFT(RIGHT('000000' + CAST(TIME_TRX AS varchar), 6), 2) + ':' + SUBSTRING(LEFT(RIGHT('000000' + CAST(TIME_TRX AS varchar), 6), 4), 3, 2) AS ClockTime, DATE_TRX, SEQ_REC, ROWID FR
SELECT
TOP (100) PERCENT
ID_BADGE,
LEFT(RIGHT('000000' + CAST(TIME_TRX AS varchar), 6), 2)
+ ':' + SUBSTRING(LEFT(RIGHT('000000' + CAST(TIME_TRX AS varchar), 6), 4), 3, 2) AS ClockTime,
DATE_TRX, SEQ_REC, ROWID
FROM
omi.TAHIST_ZERO
WHERE
(ID_BADGE = ' ' + @Badge)
AND (DATE_TRX BETWEEN @Date AND @Date2)
AND (SEQ_REC IN ('0', '1000'))
AND (CODE_TRX IN ('100', '101'))
ORDER BY
DATE_TRX, TIME_TRX
我创建了下表:
使用Reporting Services表达式我想从时钟时间的第三个值中减去时钟时间的第二个值
我浏览了VB函数,找到的都是First、Last、Min和Max,而不是second或third。我认为您可以使用SSRS Previous函数实现这一点:
谷歌做到了。第二点。可能这里的关键字是“”,而不是在T-SQL中,我试图通过VB表达式来实现这一点。